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sleet_krkn [62]
1 year ago
13

What is the IUPAC name of the following compound a. (R)-3-chloro-1-methylcyclohexene b. (S)-3-chloro-1-methylcyclohexene c. (R)-

1-chloro-3-methyl-2-cyclohexene d. (S)-1-chloro-3-methyl-2-cyclohexene
Chemistry
1 answer:
nikklg [1K]1 year ago
7 0

The answer is: (R)-1-chloro-3-methyl-2-cyclohexene.

R- and S- configuration: The nomenclature "right-handed" and "left-handed" is used to name the enantiomers of a chiral compound. Stereocenters are indicated as R or S.

How can the R- and S- configuration is assigned to a structure.

  • We must first identify the carbon(s) with the four distinct groups (atoms) connected in order to designate an absolute configuration. These are called centers of chirality.
  • Give each atom attached to a chiral center a priority based on its atomic number. The higher the atomic number, the higher the priority.
  • Draw an arrow starting at priority one and going to priority two and then to priority 3:
  • If the arrow goes clockwise, as in this case, the absolute configuration is R configuration.
  • In contrast, if the arrow goes counter-clockwise, then the absolute configuration is S configuration.
  • Now, the given structure is (shown in image). The priority is given as ( image 2). As the priority is going clockwise, thus the configuration is 'R'.
  • Hence, the IUPAC name of compound is-  (R)-1-chloro-3-methyl-2-cyclohexene.

To learn more about R- and S- configuration visit: brainly.com/question/16812236

#SPJ4

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B) Quelle est la masse de tétraoxyde de trifer (Fe3O4) produite si 3,60 moles de trioxyde de
hram777 [196]

Answer:

626,4 g de Fe₃O₄

Explanation:

Nous commencerons par écrire l'équation équilibrée de la réaction entre le fer (Fe) et le trioxyde d'aluminium. Ceci est donné ci-dessous:

9Fe + 4Al₂O₃ -> 3Fe₃O₄ + 8Al

De l'équation équilibrée ci-dessus,

4 moles d'Al₂O₃ ont réagi pour produire 3 moles de Fe₃O₄.

Par conséquent, 3,6 moles d'Al₂O₃ réagiront pour produire = (3,6 × 3) / 4 = 2,7 moles de Fe₃O₄

Ainsi, 2,7 moles de Fe₃O₄ sont produites à partir de la réaction.

Enfin, nous déterminerons la masse massique de Fe₃O₄ produite par la réaction. Ceci peut être obtenu comme suit:

Mole de Fe₃O₄ = 2,7 moles

Masse molaire de Fe₃O₄ = (3 × 56) + (4 × 16)

= 168 + 64

= 232 g / mol

Masse de Fe₃O₄ =?

Mole = masse / masse molaire

2,7 = Masse de Fe₃O₄ / 232

Croiser multiplier

Masse de Fe₃O₄ = 2,7 × 232

Masse de Fe₃O₄ = 626,4 g

Par conséquent, 626,4 g de Fe₃O₄ sont produits à partir de la réaction

7 0
2 years ago
The reaction shown below has a positive enthalpy change and a negative entropy change. 2C (s) + 2H2 (g) yields C2H4 (g) Which of
Drupady [299]
Answer is: <span>The reaction will not be spontaneous at any temperature.

</span>

<span>Gibbs free energy (G) determines if reaction will proceed spontaneously.
ΔG = ΔH - T·ΔS.
ΔG - changes in Gibbs free energy.
ΔH - changes in enthalpy.
ΔS - changes in entropy.
T is temperature in Kelvins.
When ΔS < 0 (negative entropy change) and ΔH > 0 (endothermic reaction), the process is never spontaneous (ΔG> 0).</span>

5 0
3 years ago
Why is ocean water more dense than freshwater
zalisa [80]
A. Cuz it contains more salt
Hope this helps good luck on ur examsss :))))
8 0
3 years ago
Object A has a mass of 500g and object B has a mass of 300g. Which object is more dense?
KonstantinChe [14]

Answer:

500g because 300g is less dense than 500g its kinda like a weight

Explanation:

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4 0
3 years ago
You measure 2.34 g of K2Cr2O7 into a volumetric flask. You dilute the K2Cr2O7 with water to a volume of 250 mL. It takes 35.7 mL
natta225 [31]

Answer:

0.191M of Na₂C₂O₄ is the concentration of the original Na₂C₂O₄ solution

Explanation:

The reaction of potassium dichromate, K₂Cr₂O₇ with sodium oxalate, Na₂C₂O₄ in the presence of acid H⁺ is:

K₂Cr₂O₇ + 3Na₂C₂O₄ + 14H⁺ → 2Cr³⁺ + 6CO₂ + 7H₂O + 6Na⁺ + 2K⁺

<em>Thus, 1 mole of K₂Cr₂O₇ reacts with 3 moles of Na₂C₂O₄</em>

Moles of 2.34g of K₂Cr₂O₇ (Molar mass: 294.185g/mol):

2.34g K₂Cr₂O₇ ₓ (1mol / 294.185g) = 7.954x10⁻³ moles K₂Cr₂O₇

In 250mL = 0.250L:

7.954x10⁻³ moles K₂Cr₂O₇ / 0.250L = 0.0318M K₂Cr₂O₇

Moles in 35.7mL = 0.0357L of this solution are:

0.0357L ₓ (0.0318mol / L) = <em>1.136x10⁻³ moles K₂Cr₂O</em>₇ in solution. As 1 mole of K₂Cr₂O₇ reacts with 3 moles of Na₂C₂O₄, to titrate the moles of K₂Cr₂O₇ in solution you need:

1.136x10⁻³ moles K₂Cr₂O₇ × (3 moles Na₂C₂O₄ / 1 mole K₂Cr₂O₇) =

<em>3.408x10⁻³ moles of Na₂C₂O₄</em>

In 17.8mL = 0.0178L:

3.408x10⁻³ moles of Na₂C₂O₄ / 0.0178L =

<h3>0.191M of Na₂C₂O₄ is the concentration of the original Na₂C₂O₄ solution</h3>

<em />

3 0
3 years ago
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