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alexgriva [62]
3 years ago
6

Covalent solutes are considered non-electrolytes. What does this mean for the conductivity of the solution?

Chemistry
2 answers:
svlad2 [7]3 years ago
8 0
The solution would not be able to conduct electricity because there would not be free flowing ions in the solution for electricity to travel through.
raketka [301]3 years ago
6 0

Answer: The conductivity of the solution is very low or near zero

Explanation:

Covalent compounds do not have free electrons and do not dissociate into ions. Ions are the charge carriers in solution and are responsible for the conductivity of electrolyte solutions. Non-electrolytes do not dissociate into ions hence they do not conduct electricity in solution. The conductivity is very low due to the absence of ions making the solution unable to conduct electricity.

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Based on the illustration below, explain how the different organ systems work together.
Stella [2.4K]

Answer:

this is not a proper informative question

8 0
3 years ago
Consider the following reaction between mercury(II) chloride and oxalate ion.
Alina [70]

<u>Answer:</u> The rate law of the reaction is \text{Rate}=k[HgCl_2][C_2O_4^{2-}]^2

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

2 HgCl_2(aq.)+C_2O_4^{2-}(aq.)\rightarrow 2Cl^-(aq.)+2CO_2(g)+Hg_2Cl_2(s)

Rate law expression for the reaction:

\text{Rate}=k[HgCl_2]^a[C_2O_4^{2-}]^b

where,

a = order with respect to HgCl_2

b = order with respect to C_2O_4^{2-}

Expression for rate law for first observation:

3.2\times 10^{-5}=k(0.164)^a(0.15)^b  ....(1)

Expression for rate law for second observation:

2.9\times 10^{-4}=k(0.164)^a(0.45)^b  ....(2)

Expression for rate law for third observation:

1.4\times 10^{-4}=k(0.082)^a(0.45)^b  ....(3)

Expression for rate law for fourth observation:

4.8\times 10^{-5}=k(0.246)^a(0.15)^b  ....(4)  

Dividing 2 from 1, we get:

\frac{2.9\times 10^{-4}}{3.2\times 10^{-5}}=\frac{(0.164)^a(0.45)^b}{(0.164)^a(0.15)^b}\\\\9=3^b\\b=2

Dividing 2 from 3, we get:

\frac{2.9\times 10^{-4}}{1.4\times 10^{-4}}=\frac{(0.164)^a(0.45)^b}{(0.082)^a(0.45)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[HgCl_2]^1[C_2O_4^{2-}]^2

3 0
3 years ago
Which statement is true regarding carbonic acid (H 2CO 3)? If body fluids are too alkaline, carbonic acid is excreted through th
dimaraw [331]

Answer:

the correct option is : If body fluids are too acidic, carbonic acid is excreted through the respiratory system in the form of carbon dioxide and water.

Explanation:

Metabolic acidosis is compensated by two systems, the renal and respiratory systems.

In the case of the respiratory system, the mechanism it uses to compensate for this phenomenon is to release the carbonic acid molecule dissociated into its components, that is, in the form of water and carbon dioxide.

The greater the acidosis, the more hyperventilation the person will have, and this is because they seek to eliminate carbonic acid more efficiently and quickly, along with renal excision.

The metabolic acidosis generated by carbonic acid is lethal, since the proteins in our body are denatured and the homeostasis of all systems is corrupted.

8 0
3 years ago
The reaction nacl(s) → nacl(aq) is performed in a coffee cup calorimeter, using 100 ml of h2o(l) and 5.00g of nacl. if the tempe
MrRissso [65]

Since the density of water is 1 g /mL, hence there is 100 g of H2O. So total mass is:

m = 100 g + 5 g = 105 g

 

=> The heat of reaction can be calculated using the formula:

δhrxn = m C ΔT

where m is mass, C is heap capacity and ΔT is change in temperature = negative since there is a decrease

 

δhrxn = 105 g * 4.18 J/g°C * (-2.30°C)

δhrxn = -1,009.47 J

 

=> However this is still in units of J, so calculate the number of moles of NaCl.

 

moles NaCl = 5 g / (58.44 g / mol)

moles NaCl = 0.0856 mol

 

=> So the heat of reaction per mole is:

δhrxn = -1,009.47 J / 0.0856 mol

δhrxn = -11,798.69 J/mol = -11.8 kJ/mol

5 0
3 years ago
I need help with this
lubasha [3.4K]
The answer is untestable
5 0
3 years ago
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