#78
Airplane start with initial speed

now the takeoff velocity is given as


acceelration is given as

now we have

from above equation we have


#79
Airplane start with initial speed

now the takeoff velocity is given as


acceelration is given as

now we have

from above equation we have


To solve the problem it is necessary to identify the equation in the manner given above.
This equation corresponds to the displacement of a body under the principle of simple harmonic movement.
Where,

PART A) Our equation corresponds to

Therefore the value of omega is equivalent to that of

From the definition we know that the period as a function of angular velocity is equivalent to



This same point is the equivalent of the maximum point of the speed that the body can reach, since the internal expression of the
Is equivalent to . So the maximum speed that the body can reach is,



Therefore the maximum felocity will be 5ft / s
PART B) The period of graph is the time taken to reach from one maximum point to next point maximum point, then


Answer:
H = 0.673
Explanation:
given,
side of cubical crate = 0.74
weight of the crate = 600 N
magnitude of force = 330 N
the Horizontal distance of its Center of mass
= 0.74/2
= 0.37
Let the required Height be H
By Balancing the Torques, we get
H x 330 N = 0.37 x 600
330 H = 222
H = 0.673
hence, the height above the floor where force is acting is equal to 0.673 m
True, the measurement shown is a derived unit.