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Phoenix [80]
3 years ago
15

What’s an ionic compound for magnesium and oxide?

Chemistry
2 answers:
denis23 [38]3 years ago
5 0

<u>Answer:</u> The chemical formula for the ionic compound formed will be MgO

<u>Explanation:</u>

Magnesium is the 12th element of the periodic table having electronic configuration of [Ne]3s^{2}

This element will loose 2 electrons and thus shows an oxidation state of +2 units.

Oxygen is the 8th element of the periodic table having electronic configuration of [He]2s^22p^4

This element requires 2 electrons and thus shows an oxidation state of -2 units.

By criss-cross method, the oxidation state of the ions gets exchanged and hence, they form the subscripts of the opposite ion. This results in the formation of a neutral compound.

Thus, the chemical formula for the ionic compound will be MgO

malfutka [58]3 years ago
4 0
MgO
{Mg}^{ + 2}  \: and \:   {O}^{ - 2} \\ form \: MgO
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Hydrogen is 99% 1H, 0.8% 2H, and 0.2% 3H. Calculate its average atomic mass.
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The average atomic mass of hydrogen (99% H-1, 0.8% H-2, and 0.2% H-3) is 1.012 amu.    

The average atomic mass of hydrogen can be calculated with the following equation:

A = m_{H-1}\%_{H-1} + m_{H-2}\%_{H-2} + m_{H-3}\%_{H-3}

Where:

m_{H-1}: is the mass of protium (H-1) = 1

m_{H-2}: is the <em>mass</em> of deuterium (H-2) = 2

m_{H-3}: is the <em>mass </em>of tritium (H-3) = 3

\%_{H-1}: is the abundance percent of H-1 = 99%

\%_{H-2}: is the <em>abundance percent</em> of H-2 = 0.8%

\%_{H-3}: is the <em>abundance percent</em> of H-3 = 0.2%

The average atomic mass is:

A = 1*99\% + 2*0.8\% + 3*0.2\%

Changing all the <u>percent values</u> into <u>decimal ones</u>, we have:

A = 0.99 + 2*0.008 + 3*0.002 = 1.012

Therefore, the average atomic mass of hydrogen is 1.012 amu.

Learn more about average atomic mass here brainly.com/question/8575403?referrer=searchResults

I hope it helps you!

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