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Phoenix [80]
3 years ago
15

What’s an ionic compound for magnesium and oxide?

Chemistry
2 answers:
denis23 [38]3 years ago
5 0

<u>Answer:</u> The chemical formula for the ionic compound formed will be MgO

<u>Explanation:</u>

Magnesium is the 12th element of the periodic table having electronic configuration of [Ne]3s^{2}

This element will loose 2 electrons and thus shows an oxidation state of +2 units.

Oxygen is the 8th element of the periodic table having electronic configuration of [He]2s^22p^4

This element requires 2 electrons and thus shows an oxidation state of -2 units.

By criss-cross method, the oxidation state of the ions gets exchanged and hence, they form the subscripts of the opposite ion. This results in the formation of a neutral compound.

Thus, the chemical formula for the ionic compound will be MgO

malfutka [58]3 years ago
4 0
MgO
{Mg}^{ + 2}  \: and \:   {O}^{ - 2} \\ form \: MgO
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5.943x10^24 molecules of H3PO4 will need how many grams of Mg(OH)2 in the reaction below? 3 Mg(OH)2 + 2 H3PO4 -------&gt; 1 Mg3(
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Answer:

Mass of Mg(OH)₂ required for the reaction = 863.13 g

Explanation:

3Mg(OH)₂ + 2H₃PO₄ -------> Mg₃(PO₄)₂ + 6H₂O

(5.943 x 10²⁴) molecules of H₃PO₄ is available fore reaction. Mass of Mg(OH)₂ required for reaction.

According to Avogadro's theory, 1 mole of all substances contain (6.022 × 10²³) molecules.

This can allow us find the number of moles that (5.943 x 10²⁴) molecules of H₃PO₄ represents.

1 mole = (6.022 × 10²³) molecules.

x mole = (5.943 x 10²⁴) molecules

x = (5.943 x 10²⁴) ÷ (6.022 × 10²³)

x = 9.87 moles

From the stoichiometric balance of the reaction,

2 moles of H₃PO₄ reacts with 3 moles of Mg(OH)₂

9.87 moles of H₃PO₄ will react with y moles of Mg(OH)₂

y = (3×9.87)/2 = 14.80 moles

So, 14.8 moles of Mg(OH)₂ is required for this reaction. We them convert this to mass

Mass = (number of moles) × Molar mass

Molar mass of Mg(OH)₂ = 58.3197 g/mol

Mass of Mg(OH)₂ required for the reaction

= 14.8 × 58.3197 = 863.13 g

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