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Phoenix [80]
3 years ago
15

What’s an ionic compound for magnesium and oxide?

Chemistry
2 answers:
denis23 [38]3 years ago
5 0

<u>Answer:</u> The chemical formula for the ionic compound formed will be MgO

<u>Explanation:</u>

Magnesium is the 12th element of the periodic table having electronic configuration of [Ne]3s^{2}

This element will loose 2 electrons and thus shows an oxidation state of +2 units.

Oxygen is the 8th element of the periodic table having electronic configuration of [He]2s^22p^4

This element requires 2 electrons and thus shows an oxidation state of -2 units.

By criss-cross method, the oxidation state of the ions gets exchanged and hence, they form the subscripts of the opposite ion. This results in the formation of a neutral compound.

Thus, the chemical formula for the ionic compound will be MgO

malfutka [58]3 years ago
4 0
MgO
{Mg}^{ + 2}  \: and \:   {O}^{ - 2} \\ form \: MgO
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Substance X has a fixed volume, and the attraction between its particles is strong. Substance Y has widely spread out particles
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Answer: X is a Solid; Y is a Gas

Explanation:

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3 years ago
A block of metal has a mass of 0.0694 kg. It displaces 3.6 mL of water. What is it’s density in g/cm^3
Ivan

Answer:

19.28 g/cm^3 to the nearest hundredth.

Explanation:

The volume of water displaced = the volume of the metal.

density = mass / volume

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=  69.4 g.

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3 years ago
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2 years ago
Read 2 more answers
A gaseous mixture consisting of nitrogen, argon, and oxygen is in a 3.5-L vessel at 25C. Determine the number of moles of oxygen
Step2247 [10]

Answer:

Number of moles of oxygen = 0.037  mol

Explanation:

Given data:

Total pressure = 98.5 KPa

Partial pressure of nitrogen = 22.0 KPa

Partial pressure of argon = 50.0 KPa

Volume = 3.5 L

Temperature = 25°C (25+273= 298K)

Number of moles of oxygen = ?

Solution:

Total pressure = P(N₂) + P(O₂) + P(Ar)

98.5 KPa = 22.0 KPa +P(O₂) + 50.0 KPa

98.5 KPa = 72.0 KPa +P(O₂)

P(O₂)  = 98.5 KPa - 72.0 KPa

P(O₂)  = 26.5 KPa

KPa to atm:

26.5 KPa/ 101 = 0.262 atm

Number of moles of oxygen:

PV = nRT

n = PV/RT

n = 0.262 atm × 3.5 L / 0.0821 atm.L/mol.K  × 298 K

n = 0.917atm.L /24.47atm.L/ mol

n = 0.037  mol

6 0
3 years ago
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