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goldenfox [79]
3 years ago
13

According to newtons third law forces always occur in equal but____ pairs?

Chemistry
1 answer:
arsen [322]3 years ago
8 0
'Every action has an equal but opposite reaction' They are equal, but opposite.
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Please help me i’m in need!
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Name the following compound: HNO3
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Im pretty sure it nitric acid
5 0
3 years ago
Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm
8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

\frac{dV}{dt}=10\frac{cm^3}{s}

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

\frac{dh}{dt} = ?*\frac{dV}{dt}

Of course, ?=\frac{dh}{dV}.

Now, since the volume of a cone is V=\pi r^2h/3 and the ratio r/h=15/20=3/4 or r=3/4h, the volume becomes:

V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3

We proceed to its differentiation:

\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}

Then, we compute \frac{dh}{dt}

\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}

Finally, at h=2:

\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}

Best regards.

4 0
3 years ago
What is the poH of a<br> 4.8 x 10-10 M H+ solution?
stiks02 [169]

Answer: pOH = 4.68

Explanation:

pOH = 14 - pH

pH = - Log [H+]

= - Log [4.8 x 10^-10]

= -(-9.32)

pH =+9.32

Therefore, pOH= 14 - 9.32

= 4.68

6 0
3 years ago
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