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CaHeK987 [17]
3 years ago
8

Use the following scenario to answer the question: A cell has an antiport protein on its apical surface. The cell is placed in a

solution that contains a high concentration of Na+ relative to the inside of the cell, and a high concentration of Ca⁺⁺ relative to the inside of the cell. The antiporter will move 3 Na⁺ into the cell in exchange for one Ca⁺⁺ leaving the cell. This is an example of what type of transport?
Chemistry
1 answer:
balu736 [363]3 years ago
6 0

Answer:

The correct answer is "Secondary active transport".

Explanation:

Secondary active transport is a form of across the membrane transport that involves a transporter protein catalyzing the movement of an ion down its electrochemical gradient to allow the movement of another molecule or ion uphill to its concentration/electrochemical gradient. In this example, the transporter protein (antiporter), move 3 Na⁺ into the cell in exchange for one Ca⁺⁺ leaving the cell. The 3 Na⁺ are the ions moved down its electrochemical gradient and the one Ca⁺⁺ is the ion moved uphill its electrochemical gradient, because Na+ and Ca⁺⁺are more concentrated in the solution than inside the cell. Therefore, this scenario is an example of secondary active transport.

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Answer:

Explanation:

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3 years ago
Which of the following apply to gases. Select all that apply.
melamori03 [73]

Explanation:

In gases the molecules are held together by weak Vander waal forces. Due to this they have more kinetic energy and they tend to diffuse at a faster rate because of more number of collisions between the molecules.

That is why, its molecules readily spread into the atmosphere as compared to the molecules of solids and liquids. Also, when molecules of a gas collide with the walls of a container then they tend to come back at their initial position for a fraction of second or more.

Hence, gas collisions are elastic in nature.

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4 0
4 years ago
Benzophenone has a normal freezing point of +48.1 oC, with freezing point depression constant Kfpt = − 9.78 oC/m. A 0.1500 molal
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i = 2.79

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3 years ago
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