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olga2289 [7]
2 years ago
9

A gas occupies 5.31 liters at a pressure of 0.55 atm. Determine the volume at standard pressure.

Chemistry
1 answer:
yuradex [85]2 years ago
7 0

Answer:

Option A; V =  2.92 L

Explanation:

If we assume a lot of things, like:

The gas is an ideal gas.

The temperature is constant.

The gas does not interchange mass with the environment.

Then we have the relation:

P*V = n*R*T = constant.

Where:

P = pressure

V = volume

n = number of moles

R = constant of the ideal gas

T = temperature.

We know that when P = 0.55 atm, the volume is 5.31 L

Then:

(0.55 atm)*(5.31 L) = constant

Now, when the gas is at standard pressure ( P = 1 atm)

We still have the relation:

P*V = constant = (0.55 atm)*(5.31 L)

(1 atm)*V = (0.55 atm)*(5.31 L)

Now we only need to solve this for V.

V = (0.55 atm/ 1 atm)*(5.31 L) = 2.92 L

V = 2.92 L

Then the correct option is A.

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Magnesium reacts with hydrochloric acid to produce magnesium chloride and hydrogen gas. Write a balanced chemical equation for t
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Answer:

The balanced chemical equation is Mg + 2HCl ⇒ MgCl2 + H2

The molarity of the hydrochloric acid solution is HCl 0.04 M and the pH = 1.4.

The volume of hydrogen gas produced by the reaction of 0.510 g of Mg will be 0.482 L.

Explanation:

First, for the balanced equation you have to consider the oxidation state of the elements to find subscripts. Then you can find the correct coeficients. Mg= +2, Cl = -1.

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Finally, from the balanced equation and the findings described, and considering that at 25°C and 1.00 atm 1 mol of gas has volume of 24.1 L.

1 mol H2----------- 24.1 L

0.02 mol H2----- x= 0.482L.

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