All categories

3 years ago

What occurs when a cell engulfs large food particals

1 answer:

3 0

when a cell surounds large particles it is called phagocytosis this should not be confused with pinocytosis, which is intended for small molecules

You might be interested in

Which bases can deprotonate acetylene? the pka values of the conjugate acids are given in parentheses. select all that apply. ch

Usimov [2.4K]

pKa is a value which is related to the acid dissociation constant Ka

pKa = -log Ka

i.e. Ka = 10^-pKa

The deprotonation reaction of acetylene is:

HC≡CH ↔ HC≡C⁻ + H⁺

pKa (HC≡CH) = 25

Solvents with pKa greater than 25 will deprotonate acetylene.

Ans: CH2=CH⁻ pka = 44 and CH3NH⁻ pka = 40

4 0

4 years ago

In a certain compound of iron and oxygen, FexOy, it is found that a sample of this compound weighing 6.285 g contains 4.396 g of

saveliy_v [14]

Answer:

Formula of oxide is $Fe_{2}O_{3}$

Explanation:

The given compound consists of Fe and O.

So, mass of oxygen in sample = (mass of sample) - (mass of Fe in sample)

= (6.285 g ) - (4.396 g)

= 1.889 g

Molar mass of O = 16 g/mol and molar mass of Fe = 55.845 g/mol

So, ratio of number of moles of Fe and O (Fe : O)

= $\frac{4.396}{55.845}:\frac{1.889}{16}$

= 0.0787 : 0.118

= $1:\frac{0.118}{0.0787}$

= 1 : 1.5

= 2 : 3

So, formula of oxide is $Fe_{2}O_{3}$

5 0

3 years ago

How are radioisotopes different from the standard form of an element

meriva

Answer:

Different isotopes of the same element have the same number of protons in their atomic nuclei but differing numbers of neutrons. Radioisotopes are radioactive isotopes of an element. They can also be defined as atoms that contain an unstable combination of neutrons and protons, or excess energy in their nucleus.

6 0

3 years ago

Milk of magnesia is often taken to reduce the discomfort associated with acid stomach or heartburn. The recommended dose is 1 te

Igoryamba

Answer:

8.61 mL of the HCl solution

Explanation:

The reaction that takes place is:

2HCl + Mg(OH)₂ → MgCl₂ + 2H₂O

From the given mass of Mg(OH)₂, we can calculate <u>the moles of HCl that are neutralized</u>:

4x10² mg = 400 mg = 0.400g

0.400g Mg(OH)₂ ÷ 58.32g/1mol = 6.859*10⁻³ mol Mg(OH)₂

6.859*10⁻³ mol Mg(OH)₂ * $\frac{1molHCl}{1molMg(OH)_{2}} =$ 3.429x10⁻³ mol HCl

Finally, to calculate the volume of an HCl solution, we need both the moles and the concentration. We can <u>calculate the concentration using the pH value</u>: