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Alborosie
3 years ago
5

What are the products when anaerobic respiration occurs in yeast cells?

Chemistry
2 answers:
DochEvi [55]3 years ago
7 0
<span>carbon dioxide, water, and ATP

</span>
kicyunya [14]3 years ago
5 0
The correct answer is the second option. Anaerobic respiration is a type of respiration which involves the use of electron acceptors other than oxygen. This is respiration without using oxygen. An example is alcohol fermentation where the the reactants are glucose and enzymes forming to products which are CO2, ethanol and energy.
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if you are asked to help the laboratory assistant in separating the mixture which method will you see?​
FromTheMoon [43]

Answer:

use secondary data. the normal method to use

3 0
3 years ago
What is the energy of a photon that emits a light of frequency 7.21 x 1014 Hz? A. 4.78 x 10-19 J B. 2.76 x 10-19 C. 1.0910-19 J
bazaltina [42]

Answer:

E = 4.78×10^−19 J

Explanation:

The chemical equation for the energy of a photon is given by:

E =hν , where h is the Planck constant and ν is the frequency.

E =hν = 6.626×10^−34 Js × 7.21×10^ 14

s−1 = 4.78 × 10^−19 J

5 0
3 years ago
Read 2 more answers
At pH= 8, which species is most likely to predominate in solution? pKa (-NH3+) = 9.9, pKa (-COOH) = 2.3
PtichkaEL [24]

Answer:

The NH3 + with a PKa = 9.9

Explanation:

The Pka is a mathematical expression to express the dissociation grade of a substance in a solution, that means with a substance with a pKa small is a strong acid, and in this case since the solution pH is 8, that mean that the substance with high pKa ( lower acid strength)  will predominate in a pH of 8.

7 0
4 years ago
A. Phenol (C6H5OH) is an aromatic compound and a colourless liquid widely used in household products
Olin [163]

Because there are 2 Cl on the left, we will put a coefficient 2in front of HCl on the right side to balance out the Cl. This would result in an unequal amount of H, with 6 on the right side and 7 in the left, so we have to put a coefficient of 2 in front of C6H5OH and C6H4OH on both sides to balance out the H. By doing this, we would obtain an equal amount of H on both sides. The Carbon is already balanced, and so is the Oxygen.

8 0
3 years ago
Cuantos gramos de hidróxido de calcio se necesitan para preparar 875ml de solución al 2M​
PtichkaEL [24]

Answer:

129,66 g

Explanation:

Desde,

Número de moles = concentración * volumen

concentración = 2 M

volumen = 875 ml

Número de lunares = 2 * 875/1000

Número de lunares = 1,75 moles

Número de moles = masa / masa molar

masa molar de hidróxido de calcio = 74.093 g / mol

1,75 moles = masa / 74,093 g / mol

masa = 1,75 moles * 74,093 g / mol

masa = 129,66 g

7 0
3 years ago
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