A compound having an approximate molar mass of 165 - 170 g has the following...
1 answer:
Answer:
Find ratio of atoms for empirical formula, divide mass by atomic mass
C=42.87/12 = 3.57
H= 3.598/1 = 3.598
O= 28.55/16 = 1.784
N= 25.00/14 =1.1785
to see ratio, divide by smallest no
Gives C2H2ON for empirical formula
Empirical mass = 24 +2 +16 + 14 = 56
165 to 170 /56 = 3
so molecular formula = empirical formula x 3= C6H6O3N3
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