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mina [271]
3 years ago
12

You have a board, wood blocks, and a toy car. Your goal is to build a ramp that sends the car as far across the floor as possibl

e. What angle between the board and floor would be best? Explain your answer
Chemistry
2 answers:
lakkis [162]3 years ago
5 0

Answer:

<h3><u><em>The board should be placed at about an 80-88 degrees angle. </em></u></h3>

<u><em>Explanation:</em></u>

<u><em>This will speed the car up and increase its speed as going down the ramp.</em></u>

-Dominant- [34]3 years ago
5 0

Potential and Kinetic Energy

Set up a basic ramp against a chair, on top of some books, or from a table to the floor. Hold the car at the top of the ramp, and release to demonstrate the two main kinds of energy. Potential energy is placed into the car when it's lifted from the floor, and that energy is released as the car rolls down the ramp. Ramps should be made of a solid, smooth and rigid material such as wood or plywood.

Friction

Using the ramp from earlier, you can make a more interesting experiment by placing some things at the bottom. Drop the car from the top of the ramp again, and measure how far it rolls this time. Now, place a sheet of cardstock at the bottom of the ramp, and let the car roll over that. Measure the distance it rolls. Place some sandpaper on top of the card stock, release the car, and measure that distance. Finally, try it with some carpet at the bottom. You've now learned something about friction: the card stock has a lot less friction than the carpet, so the car should be able to roll farther.

Inertia

Place a heavy stack of books a few feet from the end of the ramp, so that the car hits those books when it rolls from the top down. Demonstrate that once or twice, and then take a small ball of clay or putty. Place it on top of the car and pat it down slightly; don't squish it onto the car, but press it just enough so that it won't roll off. Roll the car down the ramp, and when it hits the books, the clay should fly off the front of the car. This happens because of Newton's first law of motion: anything moving is going to want to keep moving (until it crashes into a wall).

Angle

The optimal angle for the board is about 80⁰

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What is the pressure in millimeters of mercury of 0.0130 molmol of helium gas with a volume of 210. mLmL at 55 ∘C∘C? (Hint: You
juin [17]

Answer : The pressure of the helium gas is, 1269.2 mmHg

Explanation :

To calculate the pressure of the gas we are using ideal gas equation:

PV=nRT

where,

P = Pressure of He gas = ?

V = Volume of He gas = 210. mL = 0.210 L    (1 L = 1000 mL)

n = number of moles He = 0.0130 mole

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of He gas = 55^oC=273+55=328K

Putting values in above equation, we get:

P\times 0.210L=0.0130mole\times (0.0821L.atm/mol.K)\times 328K

P=1.67atm=1269.2mmHg

Conversion used : (1 atm = 760 mmHg)

Thus, the pressure of the helium gas is, 1269.2 mmHg

4 0
3 years ago
2. The density of helium is 1.78 X 104 g/cm. What is this<br> density in Dg/um??
Zepler [3.9K]

Answer:

d=1.78\times 10^{-7}\ Dg/\mu m^3

Explanation:

Given,

The density of Helium is 1.78\times 10^4\ g/cm^3

We need to find the density in Dg/μm

We know that,

1 g = 10 dg

1 cm³ = 10¹² μm³

So,

d=1.78 \times 10^4\ g/cm^3\\\\=1.78 \times 10^4\times \dfrac{10\ dg}{10^{12}\ \mu m^3}\\\\=1.78\times 10^{-7}\ Dg/\mu m^3

So, the density of Helium is equal to 1.78\times 10^{-7}\ Dg/\mu m^3.

4 0
3 years ago
A scuba diver with a local Sheriff’s office has been assigned the task of retrieving a sunken vessel in the Ocean. The vessel is
n200080 [17]
First, we convert the depth of the water into meters. This is:
60 feet = 18.3 meters

Now, we compute the additional pressure exerted due to the water, which is given by:
Pressure = density * gravitational field strength * height
P = 1000 * 9.81 * 18.3
P = 179.5 kPa

The atmosphere pressure is 101.325 kPa
The pressure of the gas bubbles 60 feet under water will be:
179.5 + 101.325 = 280.825 kPa

The pressure at the surface of the water will be equal to the atmospheric pressure, 101.325 kPa.

Because of this decrease in external pressure as gas bubbles rise, they are seen to expand.
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3 years ago
What are the advantages and disadvantages of common names? ( mention one advantage and one disadvantage)
Novay_Z [31]

Explanation:

Advantages of Common Names

The main advantage of using common plant names is ease of usage and common understanding in certain geographical areas and, conversely, the prevention of confusion among the laymen who do not understand Latin

.What are the disadvantages of common names?

These names may not be same every where in all places so in order to have universally similar name.

Creates confusion among different languages.

Cannot identify one particular species by common names.

8 0
3 years ago
a sample of natural gas contains 8.24 moles of methane, 0.421 moles of ethane, and 0.116 moles of propane. if the total pressure
Varvara68 [4.7K]

The partial pressure (Px) of a gas in a gas mixture is equal to its mole fraction (Xi) multiplied by the total pressure (P) of the gas mixture. That means that we have to calculate the mole fraction of each gas, then calculate its partial pressure. The mole fraction of a gas is its number of moles (n) divided by the total number of moles.

$$ Mole fraction of methane: \\$\chi_{\text {methane }}=\frac{\mathrm{n}_{\text {methane }}}{\mathrm{n}_{\text {total }}} \chi_{\text {methane }}=\frac{8.24 \mathrm{~mol}}{8.24 \mathrm{~mol}+0.421 \mathrm{~mol}+0.116 \mathrm{~mol}} \chi_{\text {methane }}=\frac{8.24 \mathrm{~mol}}{8.78 \mathrm{~mol}} \chi_{\text {methane }}=0.938$

$$Partial Pressure of methane:\\$\mathrm{P}_{\text {methane }}=\chi_{\text {methane }} \times \mathrm{PP}_{\text {methane }}=0.938 \times 1.37 \mathrm{~atm} \mathbf{P}_{\text {methane }}=\mathbf{1 . 2 8} \mathbf{~ a t m}$

$$Mole fraction of ethane: \\$\chi_{\text {ethane }}=\frac{\mathrm{n}_{\text {ethane }}}{\mathrm{n}_{\text {total }}} \chi_{\text {ethane }}=\frac{0.421 \mathrm{~mol}}{8.78 \mathrm{~mol}} \chi_{\text {ethane }}=0.0479$

$$Partial pressure of ethane:\\$\mathrm{P}_{\text {ethane }}=\chi_{\text {ethane }} \times \mathrm{PP}_{\text {ethane }}=0.0479 \times 1.37 \mathrm{~atm} \mathrm{P}_{\text {ethane }}=\mathbf{0 . 0 6 5 6} \mathbf{~ a t m}$

$$Mole fraction of propane:\\$\chi_{\text {propane }}=\frac{\mathrm{n}_{\text {propane }}}{\mathrm{n}_{\text {total }}} \chi_{\text {propane }}=\frac{0.116 \mathrm{~mol}}{8.78 \mathrm{~mol}} \chi_{\text {propane }}=0.0132$

<h3>What is Dalton’s Law?</h3>

Dalton's law of partial pressures is a gas law that states that the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures exerted by each individual gas in the mixture. The mole fraction of a given gas in a gas mixture is equal to the ratio of the partial pressure of that gas to the total pressure exerted by the gas mixture. This mole fraction can also be used to calculate the total number of moles of constituent gas if the total number of moles of the mixture is known. In addition, the mole fraction can also be used to calculate the volume of a certain gas in a mixtur.

To learn more about Dalton’s Law, visit:

brainly.com/question/14119417

#SPJ4

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1 year ago
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