<span>The answer to question 2 is C. A magnifying glass is an example of a plano-convex lens, where one side of the lens is flat and the other is a convex curve. The answer to question 3 is either B or C. A converging lens is curved on both sides and so the rays of light coming out of it converge at a point, which is known as the focal point. When the object is inside the focal point, the image is real and inverted. If it is inside the focal point, the image is virtual and upright. Therefore the image in this question will be upright. The focal length is the distance between the image that is being magnified and the centre of the magnifying lens. A real image can only be formed when the object is further away from the lens than the focal length. Therefore, in this question, the image is virtual, as the object is closer to the lens than the focal length. The answer to question 4 is D because the index of refraction cannot be less than 1. The answer to question 5 is D because only concave mirrors can produce real images; other types produce virtual images. For question 6, the answer is D. In the rainbow, each of the colours refracts at a slightly different angle; red has the smallest refractive index and violet the largest. Of the options, orange is closest to red. For question 12, A is the answer. A higher operating temperature is not a reason fluorescent lamps are better than incandescent lamps because they have a lower operating temperature. Question 15: all of these are characteristics of different electromagetic waves. For question 18, B is true - special care must be taken when low illuminance is required to reduce glare. The answer to question 19 is B - a compound microscope makes use of two lenses. For question 20, the answer is 5 meters away. The illuminance (E) is equal to light intensity (I) divided by the square distance from the light source (d). Therefore, 4 = 100/d squared. To switch this around, d squared is equal to 100/4 = 25. Then find the square root of 25, which is 5.</span>
The false positive from the response of hydrogen peroxide and the immunizing circle would be created by poor specificity. The recipe for specificity is TN/TN+FP. False-positive outcomes can be ascribed to meddling substances in nature where the strips are put away or utilized, for example, hydrogen peroxide (H2O2) or fade (hypochlorite).
The combustion of Methane produces CO₂ and water;
CH₄ + 2 O₂ → CO₂ + 2 H₂O
According to balance equation,
1 Mole of CH₄ on combustion give = 2 Moles of H₂O
So,
2 Moles of CH₄ will produce = X Moles of H₂O
Solving for X,
X = (2 Moles × 2 Moles) ÷ 1 Mole
X = 4 Moles
Result:
4 Moles of H₂O is produced on combustion of 2 Moles of CH₄.
Answer: 252.5 kPa
Explanation:
Given that:
initial volume of gas V1 = 5.00 L
initial pressure of gas P1 = 101 kPa.
new Volume V2 = 2.00 L
new pressure P2 = ?
Since, only pressure and volume are involved, apply the formula for Boyle's law
P1V1 = P2V2
101 kPa x 5.0L = P2 x 2.00L
505 = P2 x 2.00L
P2 = 505/2.00
P2 = 252.5 kPa
Thus, the new pressure of gas inside the piston is 252.5 kPa