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Inga [223]
3 years ago
15

How many grams is 3.35 moles of hcl

Chemistry
1 answer:
lions [1.4K]3 years ago
7 0
Do this

3.35mol HCl | 34.46g HCl
------------------------------------
          1          | 1mol HCl
Multiply all the numbers on top by all the numbers on bottom.

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Two samples of matter differ in temperature by 20°C. What is the difference in temperature of these two samples using the Kelvin
anyanavicka [17]

Answer:

The difference is 293.15 Kelvin.

Explanation:

Given data:

Temperature difference of matter = 20°C

Temperature difference of matter in kelvin = ?

Solution;

Formula:

0°C +273.15

now we will put the values instead of 0.

20°C + 273.15 = 293.15 K

Thus, the temperature difference between two sample is 293.15 K.

5 0
3 years ago
Which phrase best describes how scientists use the data they collect
lozanna [386]

Answer:

The correct answer is b

7 0
3 years ago
Read 2 more answers
The following balanced equation shows the decomposition of ammonia (NH3) into nitrogen (N2) and hydrogen (H2). 2NH3 → N2 + 3H2 A
Triss [41]
The decomposition of ammonia is characterized by the following decomposition equation:
                                  2NH₃<span>   →   N</span>₂  <span> +   3H</span>₂   

The mole ratio of N₂  :  H₂  is  1  :  3

    If the number of moles of N₂  =  0.0351 mol
    Then the number of moles of H₂  =  0.0351 mol  × 3
                                                         = 0.1053 mol

The number of moles of hydrogen gas produced when 0.0351 mol of Nitrogen gas is produced after the decomposition of Ammonia is  0.105 mol (OPTION 3).

6 0
3 years ago
Read 2 more answers
Calculate the change in the kinetic energy (KE) of the bottle when the mass is increased. Use the formula
DerKrebs [107]

Answer:

1 kg

2 kg

3 kg

4 kg

Explanation:

i did the assignment

8 0
3 years ago
A sample of ammonia ^NH3h gas is completely decomposed to nitrogen and hydrogen gases over heated iron wool. If the total pressu
icang [17]

Answer : The partial pressure of N_2 and H_2 is, 216.5 mmHg and 649.5 mmHg

Explanation :

According to the Dalton's Law, the partial pressure exerted by component 'i' in a gas mixture is equal to the product of the mole fraction of the component and the total pressure.

Formula used :

p_i=X_i\times p_T

X_i=\frac{n_i}{n_T}

So,

p_i=\frac{n_i}{n_T}\times p_T

where,

p_i = partial pressure of gas

X_i = mole fraction of gas

p_T = total pressure of gas

n_i = moles of gas

n_T = total moles of gas

The balanced decomposition of ammonia reaction will be:

2NH_3\rightarrow N_2+3H_2

Now we have to determine the partial pressure of N_2 and H_2

p_{N_2}=\frac{n_{N_2}}{n_T}\times p_T

Given:

n_{N_2}=1\\\\n_{H_2}=3\\\\n_{T}=4\\\\p_T=866mmHg

p_{N_2}=\frac{1}{4}\times (866mmHg)=216.5mmHg

and,

p_{H_2}=\frac{n_{H_2}}{n_T}\times p_T

Given:

n_{H_2}=1\\\\n_{H_2}=3\\\\n_{T}=4\\\\p_T=866mmHg

p_{H_2}=\frac{3}{4}\times (866mmHg)=649.5mmHg

Thus, the partial pressure of N_2 and H_2 is, 216.5 mmHg and 649.5 mmHg

5 0
4 years ago
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