Siny/2.7=sin63/2.8
siny=2.7sin63/2.8
y=arcsin((2.7sin63)/2.8)
y≈59.23° (to nearest one-hundredth of a degree)
The distance formula is given by:
We are given two points A and B as
A(1,1) and
B(7,-7)
so we have ,
x1 = 1 , y1=1
x2= 7 and y2=-7
Plugging these in the formula we have:
d=√(36+64)
d=√100
d=10
Answer: The distance between A(1,1) and B(7,-7) is 10
The picture in the attached figure
we know that
RX+RA+XA=24
XA=24-RA-RX------> XA=24-11-4----> XA=9
XA=XP+PA
so
XP+PA=9------> XP=9-PA-----> equation 1
RX/XP=RA/PA
11*XP=4*PA-----> equation 2
substitute equation 1 in equation 2
11*[9-PA]=4*PA-----> 99-11*PA=4*PA----> 15*PA=99----> PA=99/15
PA=6.6
XP=9-PA-----> XP=9-6.6----> XP=2.4
the answer is the option<span>
B. XP = 2.4, PA = 6.6 </span>
Answer:
0.0010,0.2743
Step-by-step explanation:
Given that Stanford–Binet IQ Test scores are normally distributed with a mean score of 100 and a standard deviation of 15
If x represents the scores then
X is N(100,15)
a) See enclosed file
b) Z score =
c) the probability that a randomly selected person has an IQ test score
i. Over 145.
=
ii. Under 91
=