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LuckyWell [14K]
3 years ago
7

Which of the following solutions contains the greatest number of ions?. . 1) 200.0 mL of 0.10 M iron (III) chloride. 2) 800.mL o

f 0.10 M sucrose
Chemistry
1 answer:
ahrayia [7]3 years ago
6 0
The number of ions is determined by multiplying the given volume and the molarity of the solution. The product is multiplied to the number of ions when the solution dissociates. In this case:

1. <span>200.0 mL of 0.10 M iron (III) chloride = 0.2*0.1* 4 = 0.08
2. </span><span>800.mL of 0.10 M sucrose = 0.8 * 0.1 * 1 = 0.08

The two solutions have the same number of ions. </span>
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Entropy change in an internally reversible isothermal process is _______ to the temperature of the system.
alukav5142 [94]

Answer:

Internally reversible is the answer.

Explanation:

3 0
3 years ago
Toothpaste contains Sodium fluoride which is used to prevent tooth decay. How many grams are in 1 mole NaF?
nikitadnepr [17]

The answer is 42 grams of NaF are there in 1 mole.

<h3>What is a mole ?</h3>

A mole is defined as 6.022 × 10²³ atoms, molecules, ions, or other chemical units.

and the molar mass of a substance is defined as the mass of 1 mole of that substance, expressed in grams per mole.

It is equal to the mass of 6.022 × 10²³ atoms, molecules, or formula units of that substance.

Molar Mass , i.e. mass of 1 mole of NaF is sum of molar mass of Na and F

23 + 19

42 grams

Therefore 42 grams of NaF Sodium-fluoride are there in 1 mole.

To know more about mole

brainly.com/question/26416088

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6 0
2 years ago
Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimen
olga55 [171]

Answer: Rate law=k[A]^1[B]^2, order with respect to A is 1, order with respect to B is 2 and total order is 3. Rate law constant is 3L^2mol^{-2}s^{-1}

Explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Rate=k[A]^x[B]^y

k= rate constant

x = order with respect to A

y = order with respect to A

n = x+y = Total order

a) From trial 1: 1.2\times 10^{-2}=k[0.10]^x[0.20]^y    (1)

From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (2)

Dividing 2 by 1 :\frac{4.8\times 10^{-2}}{1.2\times 10^{-2}}=\frac{k[0.10]^x[0.40]^y}{k[0.10]^x[0.20]^y}

4=2^y,2^2=2^y therefore y=2.

b) From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (3)

From trial 3: 9.6\times 10^{-2}=k[0.20]^x[0.40]^y   (4)

Dividing 4 by 3:\frac{9.6\times 10^{-2}}{4.8\times 10^{-2}}=\frac{k[0.20]^x[0.40]^y}{k[0.10]^x[0.40]^y}

2=2^x,2=2^1, x=1

Thus rate law is Rate=k[A]^1[B]^2

Thus order with respect to A is 1 , order with respect to B is 2 and total order is 1+2=3.

c) For calculating k:

Using trial 1:  1.2\times 10^{-2}=k[0.10]^1[0.20]^2

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6 0
3 years ago
A sample containing 2.30 mol of Ne gas has an initial volume of 8.00 L. What is the final volume, in liters, when the following
marta [7]

Answer:

a. 4,00L

b. 16,00L

c. 12,31L

Explanation:

Avogadro's law says:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

a. If initial conditions are 2,30mol and 8,00L and you lose one-half of atoms, that means you have 1,15mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{1,15mol}

<em>V₂ = 4,00L</em>

b. If initial conditions are 2,30mol and 8,00L and you add 2,30mol, that means you have 4,60mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{4,60mol}

<em>V₂ = 16,00L</em>

c. 25,0g of Ne are:

25,0g × (1mol / 20,1797g) = 1,24 moles of Ne. That means you have 2,30mol - 1,24mol = 3,54mol of Ne

\frac{8,00L}{2,30mol} =\frac{V_2}{3,54mol}

<em>V₂ = 12,31L</em>

I hope it helps!

6 0
4 years ago
The pathogen below is a single-celled organism without a nucleus that can cause illness in a humans.
sukhopar [10]

Answer:

bacteria

Explanation:

The pathogen below is a single-celled organism without a nucleus that can cause illness in a humans.

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