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Galina-37 [17]
3 years ago
11

Giving brain or whatever its called

Chemistry
2 answers:
Sidana [21]3 years ago
7 0

Clouds will form due to more water vapor in the air

Andru [333]3 years ago
3 0

a i am in the same home school program too! what's your teachers name?

Explanation:

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How many grams are in 4.5 moles of NaF?
Ilia_Sergeevich [38]

Answer:

3139542g

Explanation:

That's because if you talk about

4.5

moles of sodium fluoride, you would get a really absurd number of grams.

6 0
2 years ago
Which reactants would lead to a spontaneous reaction?
Igoryamba

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B. Ba2+ and Mn (nevermind its not B)

Explanation:

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Define the clinical thermometer ​
Sloan [31]

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a small medical thermometer with a short but finely calibrated range, for taking a person's temperature.

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Read 2 more answers
A 100.0 mL sample of 0.10 M Ca(OH)2 is titrated with 0.10 M HBr. Determine the pH of the solution after the addition of 300.0 mL
Vera_Pavlovna [14]

Answer : The correct option is, (C) 1.7

Explanation :

First we have to calculate the moles of Ca(OH)_2 and HBr.

\text{Moles of }Ca(OH)_2=\text{Concentration of }Ca(OH)_2\times \text{Volume of solution}=0.10M\times 0.1L=0.01mole

\text{Moles of }HBr=\text{Concentration of }HBr\times \text{Volume of solution}=0.10M\times 0.3L=0.03mole

The balanced chemical reaction will be:

Ca(OH)_2+2HBr\rightleftharpoons CaBr_2+2H_2O

0.01 mole of Ca(OH)_2 dissociate to give 0.01 mole of Ca^{2+} ion and 0.02 mole of OH^- ion

and

0.03 mole of HBr dissociate to give 0.03 mole of H^+ ion and 0.03 mole of Br^- ion

That means,

0.02 moles of OH^- ion  neutralize by 0.02 moles of H^+ ion.

The excess moles of H^+ ion = 0.03 - 0.02 = 0.01 mole

Total volume of solution = 100 + 300 = 400 ml = 0.4 L

Now we have to calculate the concentration of H^+ ion.

\text{Concentration of }H^+=\frac{\text{Moles of }H^+}{\text{Total volume}}

\text{Concentration of }H^+=\frac{0.01mole}{0.4L}=0.025M

Now we have to calculate the pH of the solution.

pH=-\log [H^+]

pH=-\log (0.025M)

pH=1.7

Therefore, the pH of the solution is, 1.7

5 0
3 years ago
10 grams CH10 + excess O2 → ? grams CO2 + H2O
Contact [7]

Answer:

20  gm  CO2

Explanation:

CH10   mole weight = ~ 22 gm

  each 22 gm CH10 produces 44 gm CO2

        44 / 22 = x / 10 = 20 gm

3 0
2 years ago
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