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aalyn [17]
3 years ago
6

Sonar is a device that uses reflected sound waves to measure underwater depths. If a sonar signal has a frequency of 288 Hz and

the speed of sound in water is 1.45 x 103 m/s, what is the wavelength of the sonar signal?
0.20 m

0.01 m

5.03 m

0.50 m
Physics
1 answer:
mart [117]3 years ago
3 0

Answer:

5.03 m

Explanation:

The wavelength of a wave is given by

\lambda=\frac{v}{f}

where

v is the speed of the wave

f is the frequency of the wave

For the sonar signal in this problem,

f=288 Hz

v=1.45\cdot 10^3 m/s

Substituting into the equation, we find the wavelength:

\lambda=\frac{1.45\cdot 10^3 m/s}{288 Hz}=5.03 m

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xxTIMURxx [149]
The area of the Earth (Ae) that is irradiated by is given by:

Ae = 4πRe^2, where Re = Distance from Sun to Earth
Substituting;
Ae = 4π*(1.5*10^8*1000)^2 = 2.827*10^23 m^2

On the Earth, insolation (We) = Psun/Ae

Therefore,
Psun (Rate at which sun emits energy) = We*Ae = 1.4*2.827*10^23 = 3.958*10^23 kW = 3.958*10^26 W
6 0
3 years ago
If the mass of a material is 87 grams and the volume of the material is 14 cm3, what would the density of the material be?
tresset_1 [31]

Answer:

6.214g/cm³

Explanation:

The question is on density of a material

Density=mass/volume

Given, mass=87grams   and volume= 14 cm³  density=?

Density=m/v 87/14 =6.214g/cm³

8 0
3 years ago
Why do areas with low altitude have warmer air than areas with high altitude
barxatty [35]

Answer:

Air at higher altitude is under less pressure than air at lower altitude because there is less weight of air above it, so it expands (and cools), while air at lower altitude is under more pressure so it contracts (and heats up).

Explanation:

Hope that helped

6 0
2 years ago
A wave of infrared light has a speed of 6m/s and a wave length of 12 m. What is the frequency of this wave?
erastovalidia [21]
Frequency = speed / wavelength

(6 m/s) / (12 m) = 0.5 Hz.

That's not infrared light.
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6 0
4 years ago
HELP IM TIMED. ILL MARK BRAINLIEST PLSSSSSS.
Alex17521 [72]

Answer:

According to Newton's Second Law of Motion :    

Where,

F = Force Applied

m = Mass of the object

a = Acceleration

Now, we will use this law to solve this question.

Given :

Acceleration or a = 15.3 m/s²

Force = 44 N

Mass = ?

Substitute, the given values in the formula.

F = ma

⇒ m = F/a

   m = 44/15.3

<u>m = 2.9 kg</u>

5 0
3 years ago
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