Answer:
Maybe B, D, F
Explanation:
It wasn’t letting me submit so it is in the link
Orbital periods of stars in the Galaxy
Answer:
the phenomenon whereby a pair of particles are generated in such a way that the individual quantum states of each are indefinite until measured, and the act of measuring one determines the result of measuring the other, even when at a distance from each other.
The result of the Mexican victory was that fallen defenders
became heroes to the cause of Texan independence.<span> The Battle of
the Alamo took place between February 23 and March 6, 1836 and became the
central episode of the Texas
Revolution . After this thirteen-day battle, the
Mexican troops of General President Antonio
Lopez de Santa Anna began an attack on San Antonio de
Bexar, the current San Antonio in Texas. The Battle of the Alamo fought the
army of Mexico against
a group of Texan rebels, mostly American settlers. More than four thousand
men from Santa Ana stood in front of
the Alamo Fort , the last stronghold of the rebels, which
barely reached 187. The Alamo was not a fortress prepared to withstand a siege.
It is believed that all the rebels of the Alamo died in the siege, but Santa
Anna came to lose up to about 900 men during the days that lasted the fight. However,
the worst result for Santa Ana was precisely the resistance that the Texan
rebels had in the Alamo, which fostered the fighting spirit of the Texans. A
few days later, on March 14, 1836, Texas became independent from Mexico and a
month later, Santa Ana was imprisoned.</span>
Answer:
3.63 s
Explanation:
We can solve the problem by using the equivalent SUVAT equations for the angular motion.
To find the angular acceleration, we can use the following equation:
![\omega_f^2 - \omega_i ^2 =2 \alpha \theta](https://tex.z-dn.net/?f=%5Comega_f%5E2%20-%20%5Comega_i%20%5E2%20%3D2%20%5Calpha%20%5Ctheta)
where
is the final angular speed
is the initial angular speed
is the angular distance covered
is the angular acceleration
Re-arranging the formula, we can find
:
![\alpha=\frac{\omega_f^2-\omega_i^2}{2\theta}=\frac{(3.14\cdot 10^4 rad/s)^2-(1.10\cdot 10^4 rad/s)^2}{2(2.00\cdot 10^4 rad)}=2.16\cdot 10^4 rad/s^2](https://tex.z-dn.net/?f=%5Calpha%3D%5Cfrac%7B%5Comega_f%5E2-%5Comega_i%5E2%7D%7B2%5Ctheta%7D%3D%5Cfrac%7B%283.14%5Ccdot%2010%5E4%20rad%2Fs%29%5E2-%281.10%5Ccdot%2010%5E4%20rad%2Fs%29%5E2%7D%7B2%282.00%5Ccdot%2010%5E4%20rad%29%7D%3D2.16%5Ccdot%2010%5E4%20rad%2Fs%5E2)
Now we want to know the time the bit takes starting from rest to reach a speed of
. So, we can use the following equation:
![\alpha = \frac{\omega_f-\omega_i}{t}](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B%5Comega_f-%5Comega_i%7D%7Bt%7D)
where:
is the angular acceleration
is the final speed
is the initial speed
t is the time
Re-arranging the equation, we can find the time:
![t=\frac{\omega_f-\omega_i}{\alpha}=\frac{7.85\cdot 10^4 rad/s-0}{2.16\cdot 10^4 rad/s^2}=3.63 s](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B%5Comega_f-%5Comega_i%7D%7B%5Calpha%7D%3D%5Cfrac%7B7.85%5Ccdot%2010%5E4%20rad%2Fs-0%7D%7B2.16%5Ccdot%2010%5E4%20rad%2Fs%5E2%7D%3D3.63%20s)