If the northern hemisphere were tilted 90° towards the sun which location would be warmer in summer the Arctic Circle or Florida

The current in a circuit is tripled by connecting a 580 resistor in parallel with the resistance of the circuit. Determine the r

const2013 [10]

Answer:

1160 ohm

Explanation:

We are given that

R'=580 ohm

Current=3 I

We have to find the resistance of the circuit.

Let R be the resistance of circuit.

In parallel

$\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}$

Using the formula

$\frac{1}{R_{eq}}=\frac{1}{580}+\frac{1}{R}=\frac{580+R}{580R}$

$R_{eq}=\frac{580R}{580+R}$

In parallel combination,Potential difference across each resistance remains same.

$V=IR$

Using the formula

$IR=3IR_{eq}$

$IR=3I\times \frac{580R}{580+R}$

$580+R=3\times 580=1740$

$R=1740-580=1160\Omega$

6 0

3 years ago

Which of the following has potential but not kinetic energy?

marissa [1.9K]

A ball sitting on a shelf:)

7 0

3 years ago

What hall voltage is produced by a 0.200-t field applied across a 2.60-cm-diameter aorta when blood velocity is 60.0 cm/s?

amm1812

The hall voltage will be calculated using the formula:

E = Blv

where:

>Hall voltage: E = ?
>Magnetic field:
B = 0.200 Tesla or Wb/m^2
>Width of conductor or Diameter of Aorta:
l = 2.60 cm, converting to meter = .0260 m
>Velocity of charge flowing:
v = 60 cm/s, converting to meter = 0.6 m/s

Substituting the given :

E = (0.200 Wb/m^2) * (0.260 m) * (0.6 m/s)
E = (0.200 Wb/m^2) * (0.156 m^2/s)
E = 0.0312 Wb/s

Since 1 volt = 1 Wb/s then,

E = 0.0312 V or 31.2 mV

8 0

3 years ago

What is the potential difference between a point 0.48 mm from a charge of 2.9 nc and a point at infinity?

Nuetrik [128]

The potential at a distance r from a charge Q is given by
$V(r) = k_e \frac{Q}{r}$
where ke is the Coulomb's constant.

The charge in our problem is $Q=2.9 nC=2.9 \cdot 10^{-9} C$ ; for the point at $r=0.48 mm=0.48 \cdot 10^{-3} m$ , the potential is
$V_1 = k_e \frac{Q}{r}= (8.99 \cdot 10^9 Nm^2 C^{-2}) \frac{2.9 \cdot 10^{-9} C}{0.48 \cdot 10^{-3} m}= 5.43 \cdot 10^4 V$

For the point at infinity, we immediately see that the potential is zero, because $r= \infty$ and so $V_2 = 0$ .

Therefore, the potential difference between the two points is
$\Delta V = V_1 - V_2 = V_1 = 5.43 \cdot 10^4 V$

6 0

3 years ago

Why VR is always less than 1 in Third class lever?

Sav [38]

Mechanical advantage of a class 3 lever is always less than 1 because the load arm is always longer than effort arm. This helps by reducing the applied force(effort).that’s your answer hope this helps you!
Have a great day!

3 0

3 years ago