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3 years ago

10

A ball is thrown at an angle of 40Â° above the horizontal at a speed of 16.0 m/s from the top of a 12.4 m tall building. What is

the maximum height of the ball above the ground?

1 answer:

spin [16.1K]3 years ago

6 0

What you do is, multiply 16.0 and 12.4 together. then multiply that by 40a

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