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s2008m [1.1K]
3 years ago
10

A ball is thrown at an angle of 40° above the horizontal at a speed of 16.0 m/s from the top of a 12.4 m tall building. What is

the maximum height of the ball above the ground?
Physics
1 answer:
spin [16.1K]3 years ago
6 0
What you do is, multiply 16.0 and 12.4 together. then multiply that by 40a
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The chart shows rate of decay. A 3 column table with 7 rows. The first column is Half-lives elapsed, with entries 0, 1, 2, 3, 4,
Romashka [77]

Answer:

A.

Explanation:

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4 years ago
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a pitcher throws a 0.35 kg ball, giving it an acceleration of 10.0 m/s. what would the acceleration be, if the pitcher threw the
german

Answer:

New acceleration is 20.0 m/s².

Explanation:

F = m*a

F = 0.35 kg * 10.0m/s²

If Force will be doubled , and mass will be the same

we can write

2F = 2*0.35 kg*10.0 m/s²=0.35kg*20.0m/s²

New acceleration is 20.0 m/s².

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4 years ago
Orbital velocity is the average speed of a planet moving through space in its orbit around the sun. Which of the following plane
labwork [276]

The force of gravity is equal to the mass times centripetal acceleration.

Fg = m v^2 / r

The force of gravity is defined by Newton's law of universal gravitation as:

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Therefore:

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MG / r = v^2

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4 0
3 years ago
A 129-kg horizontal platform is a uniform disk of radius 1.61 m and can rotate about the vertical axis through its center. A 65.
LUCKY_DIMON [66]

Answer:

Moment of inertia of the system is 289.088 kg.m^2

Explanation:

Given:

Mass of the platform which is a uniform disk = 129 kg

Radius of the disk rotating about vertical axis = 1.61 m

Mass of the person  standing on platform = 65.7 kg

Distance from the center of platform = 1.07 m

Mass of the dog on the platform = 27.3 kg

Distance from center of platform = 1.31 m

We have to calculate the moment of inertia.

Formula:

MOI of disk = \frac{MR^2}{2}

Moment of inertia of the person and the dog will be mr^2.

Where m and r are different for both the bodies.

So,

Moment of inertia (I_y_y )  of the system with respect to the axis yy.

⇒ I_y_y=I_d_i_s_k + I_m_a_n+I_d_o_g

⇒ I_y_y=\frac{M_d_i_s_k(R_d_i_s_k)^2}{2} +M_m(r_c)^2+M_d_o_g(R_c)^2

⇒ I_y_y=\frac{129(1.61)^2}{2} +65.7(1.07)^2+27.2(1.31)^2

⇒ I_y_y=289.088\ kg.m^2

The moment of inertia of the system is 289.088 kg.m^2

7 0
3 years ago
What is momentum equal to?
Setler [38]

Answer:

D

Explanation:

mass times velocity

hope this help

8 0
3 years ago
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