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3 years ago

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A ball is thrown at an angle of 40Â° above the horizontal at a speed of 16.0 m/s from the top of a 12.4 m tall building. What is

the maximum height of the ball above the ground?

1 answer:

spin [16.1K]3 years ago

6 0

What you do is, multiply 16.0 and 12.4 together. then multiply that by 40a

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The practice of science can answer only scientific questions. And scientific questions guide the design of investigations. What

meriva

The scientific question can be supported by evidence that must be true of the possible answers to a scientific question. Option D is correct,

<h3>What is a Scientific hypothesis?</h3>

A scientific hypothesis must meet two criteria, A scientific hypothesis must be testable, and a scientific hypothesis must be falsifiable The basic idea of a hypothesis is that there is no predetermined outcome.

For a solution to be termed a scientific hypothesis, it has to be an idea that can be supported or refuted through carefully crafted experimentation or observation.

Only scientific questions may be answered by scientific activity. The design of the research is also influenced by scientific issues.

The scientific question can be supported by evidence that must be true of the possible answers to a scientific question.

They are accurate regarding the scientific question and can be substantiated by proof.

Hence option D is correct.

To learn more about the hypotheses refer to the link ;

https://brainly.in/question/1769011

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6 0

2 years ago

Tectonic plates are large segments of the earth's crust that move slowly. Suppose one such plate has an average speed of 6.0 cm

faltersainse [42]

Answer:

1.35×10⁻⁷ m

37.278 mi/My

Explanation:

Speed of the tectonic plate= 6 cm/yr

Converting to seconds

$6=\frac{6}{365.25\times 24\times 60\times 60}$

So in one second it will move

$\frac{6}{365.25\times 24\times 60\times 60}$

In 71 seconds

$71\times \frac{6}{365.25\times 24\times 60\times 60}=1.35\times 10^{-5}\ cm$

The tectonic plate will move 1.35×10⁻⁵ cm or 1.35×10⁻⁷ m

Convert to mi/My

1 cm = 6.213×10⁻⁶ mi

1 M = 10⁶ years

$6\times 6.213\times 10^{-6}\times 10^6=37.278\ mi/My$

Speed of the tectonic plate is 37.278 mi/My

7 0

2 years ago

A coil has 400 turns and self-inductance 7.50 mH. The current in the coil varies with time according to i = 1680 mA2 cos [πt/(0.

zhannawk [14.2K]

Answer:

(a) 1.58 V

(b) 0.0126 Wb

(c) 0.0493 V

Solution:

As per the question:

No. of turns in the coil, N = 400 turns

Self Inductance of the coil, L = 7.50 mH = $7.50\times 10^{- 3}\ H$

Current in the coil, i = $1680cos[\frac{\pi t}{0.0250}]$ A

where

$i_{max} = 1680\ mA = 1.680\ A$

Now,

(a) To calculate the maximum emf:

We know that maximum emf induced in the coil is given by:

$e = \frac{Ldi}{dt}$

$e = L\frac{d}{dt}(1680)cos[\frac{\pi t}{0.0250}]$

$e = - 7.50\times 10^{- 3}\times \frac{\pi}{0.0250}\times \frac{d}{dt}(1680)sin[\frac{\pi t}{0.0250}]$

For maximum emf, $sin\theta$ should be maximum, i.e., 1

Now, the magnitude of the maximum emf is given by:

$|e| = 7.50\times 10^{- 3}\times 1680\times 10^{- 3}\times \frac{\pi}{0.0250} = 1.58\ V$

(b) To calculate the maximum average flux,we know that:

$\phi_{m, avg} = L\times i_{max} = 7.50\times 10^{- 3}\times 1.680 = 0.0126\ Wb$

(c) To calculate the magnitude of the induced emf at t = 0.0180 s:

$e = e_{o}sin{\pi t}{0.0250}$

$e = 7.50\times 10^{- 3}\times sin{\pi \times 0.0180}{0.0250} = 2.96\times 10^{- 4} =0.0493\ V$

7 0

3 years ago

How would i solve these problems, nobody in my class understands and there is a substitute

drek231 [11]

find acceleration force divided by Mass

a=f/m

6 0

3 years ago

What do you mean by mechanical advantage is 2.5 of a machine?

BigorU [14]

Answer:

If you are using a machine that has a mechanical advantage of 2.5,you will have increased your EFFORT DISTANCE by 2.5 times. This allows you to REDUCE the EFFORT FORCE needed by 2.5 times.

3 0

3 years ago