All categories

2 years ago

Which element has a smaller ionic radius than magnesium (Mg)?

Chemistry

1 answer:

barxatty [35]2 years ago

6 0

Answer:

Na has atomic number 11

which is less than magnesium has atomic number 12

ANSWER IS D

Explanation:

aluminum or Al is atomic 13 and Ca or calcium is atomic number 20 and rubidium or Rb is atomic number 37

You might be interested in

I WILL RATE BRAINLIEST!!!! NEED QUICK HELP!!!!

Alik [6]

You will need the Gas Law:

pV = nRT

Since T and p are constant, R is constant too, then moles increases->volume will increase with the same ratio too!

4 0

3 years ago

A rigid cylinder with a movable piston contains a sample of hydrogen gas. At 330. K, this sample has a pressure of 150. kPa and

Marta_Voda [28]

Answer:

V₂ = 4.34 L

Explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

Initial volume = 3.50 L

Initial pressure = 150 Kpa (150/101.325 = 1.5 atm)

Initial temperature = 330 K

Final temperature = 273 K

Final volume = ?

Final pressure = 1 atm

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂

V₂ = 1.5 atm × 3.50 L × 273 K / 330 K × 1 atm

V₂ = 1433.3 atm .L. K / 330 k.atm

V₂ = 4.34 L

4 0

3 years ago

How much heat is required to increase the temperature of 35.0 grams of water from 10.0°C to 45.0°C? (The specific heat of water

kati45 [8]

Q = mCΔT
Q is heat in Joules, m is mass, C is the specific heat of water, delta T is the change in temperature

Q = (35g)(4.18)(35 degrees) = 5121 Joules or 5.12 kJ required

7 0

2 years ago

Read 2 more answers

The heat of fusion for water is 80. cal/g. How many calories of heat are needed to melt a 35 g ice cube that has a temperature o

HACTEHA [7]

Answer: 2800 calories

Explanation:

Latent heat of fusion is the amount of heat required to convert 1 mole of solid to liquid at atmospheric pressure.

Amount of heat required to fuse 1 gram of water = 80 cal

Mass of ice given = 35 gram

Heat required to fuse 1 g of ice at $0^0C$ = 80 cal

Thus Heat required to fuse 35 g of ice = $\frac{80}{1}\times 35=2800cal$

Thus 2800 calories of energy is required to melt 35 g ice cube

6 0

3 years ago

The thallium Subscript 81 Superscript 208 Baseline Tl nucleus is radioactive, with a half-life of 3.053 min. At a given instant,

Genrish500 [490]

Answer: (E) 300 bq

Explanation:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

Radioactive decay process is a type of process in which a less stable nuclei decomposes to a stable nuclei by releasing some radiations or particles like alpha, beta particles or gamma-radiations. The radioactive decay follows first order kinetics.

Half life is represented by $t_{\frac{1}{2}$

Half life of Thallium-208 = 3.053 min

Thus after 9 minutes , three half lives will be passed, after ist half life, the activity would be reduced to half of original i.e. $\frac{2400}{2}=1200$ , after second half life, the activity would be reduced to half of 1200 i.e. $\frac{1200}{2}=600$ , and after third half life, the activity would be reduced to half of 600 i.e. $\frac{600}{2}=300$ ,

Thus the activity 9 minutes later is 300 bq.

7 0

2 years ago