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Oksanka [162]
3 years ago
11

Is 432 divisible by 9 I’m looking for the estimate 432 divided by 9

Mathematics
1 answer:
Monica [59]3 years ago
5 0

Answer:

Yes (432 = 9 x48).

Step-by-step explanation:

The trick you need to know is the theorem that says that if the digits in a number add up to a multiple of 9, then the number itself is divisible by 9.

So we go 4+3+2 = 9.

So as this sum of 9 is divisible by 9, it means 432 is also divisible by 9.

If you want to work out the actual answer of 432 divided by 9, you can estimate it by doing 450 ÷ 9 = 50. Then see that 432 is 18 less than 450. And 18 = 2x9. So the answer to the division is 50-2 = 48.

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Step-by-step explanation:

100-x=m

100-20=80

100-60=40

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If y equals 6 , what is the value of x given 8x plus 5y equals 62
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Can someone help me solve the inequality-2x+4>8 with the steps? Thanks
stellarik [79]

\huge\text{Hey there!}

\rm{-2x + 4 > 8}

\large\textsf{SUBTRACT  4 to BOTH SIDES}

\rm{-2x + 4 - 4 > 8 - 4}

\large\textsf{CANCEL puts 4 - 4 because that gives you 0}

\large\textsf{KEEP: 8 - 4 because that helps solve for the x-value}

\rm{8 - 4 = \boxed{\bf 4}}

\rm{NEW\  EQUATION: -2x > 4}

\large\textsf{DIVIDE -2 to BOTH SIDES}

\mathsf{\dfrac{-2}{-2}>\dfrac{4}{-2}}

\mathsf{CANCEL\  out: \dfrac{-2}{-2}\  because\  that\  gives\  you\  1}

\mathsf{KEEP: \dfrac{4}{-2} \ because \ it \ helps \you \ compare\  to \  the \ x-value }

\mathsf{\dfrac{4}{-2} = \boxed{\bf -2}}

\rm{\bold{x < -2 }}

\rm{It\ is \ an\  O PENED \ circle \  shaded \  to \ the \ left \ side \ of \ the \ number  \ line}

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8 0
3 years ago
Triangle PQR is transformed to triangle P'Q'R'. Triangle PQR has vertices P(4, 0), Q(0, −4), and R(−8, −4). Triangle P'Q'R' has
Whitepunk [10]

Answer:

Please find attached the required plot accomplished with an online tool

Part A:

1/4

Part B:

P''(-1, 0),  Q''(0, -1), and R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent

Step-by-step explanation:

Part A:

Triangle ΔPQR has vertices P(4, 0), Q(0, -4), R(-8, -4)

Triangle ΔP'Q'R' has vertices P'(1, 0), Q'(0, -1), R'(-2, -1)

The dimensions of the sides of the triangle are given by the relation;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Where;

(x₁, y₁) and (x₂, y₂) are the coordinates on the ends of the segment

For segment PQ, we place (x₁, y₁) = (4, 0) and (x₂, y₂) = (0, -4);

By substitution into the length equation, we get;

The length of segment PQ = 4·√2

The length of segment PR = 4·√10

The length of segment RQ = 8  

The length of segment P'Q' = √2

The length of segment P'R' = √10

The length of segment R'Q' = 2

Therefore, the scale factor of the dilation of ΔPQR to ΔP'Q'R' is 1/4

Part B:

Reflection of (x, y) across the y-axis gives;

(x, y) image after reflection across the y-axis = (-x, y)

The coordinates after reflection of P'(1, 0), Q'(0, -1), R'(-2, -1) across the y-axis is given as follows;

P'(1, 0) image after reflection across the y-axis = P''(-1, 0)

Q'(0, -1) image after reflection across the y-axis = Q''(0, -1)

R'(-2, -1) image after reflection across the y-axis = R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent as the dimensions of the sides of triangle PQR and P''Q''R'' are not the same.

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