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2 years ago

In chemical compounds, atoms like to have 8 electrons in their outer shell, this gives them __________.

Chemistry

2 answers:

tresset_1 [31]2 years ago

8 0

It's A
a. the electron configuration of a noble gas.

kolbaska11 [484]2 years ago

4 0

Elements try to attain their nearest noble configuration either by loosing or gaining electron(s). Hence option A.) the electron configuration of a noble gas is the correct answer. Hope this helps, have a great day/night ahead! :)

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Calculate the volume, in milliliters, for the following:

fredd [130]

Answer: The volume for 0.850 mol of $NaNO_{3}$ from a $NaNO_{3}$ solution is 1700 mL.

The volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.

Explanation:

Molarity is the number of moles of solute present in a liter of solution.

As given moles of $NaNO_{3}$ are 0.850 mol and molarity of $NaNO_{3}$ solution is 0.5 M. Hence, its volume is calculated as follows.

$Molarity = \frac{no. of moles}{Volume (in L)}\\0.5 M = \frac{0.850 mol}{Volume}\\Volume = 1.7 L (1 L = 1000 mL)\\= 1700 mL$

Therefore, the volume for 0.850 mol of $NaNO_{3}$ from a $NaNO_{3}$ solution is 1700 mL.

As given mass of LiOH are 30.0 g from a 2.70 M LiOH (molar mass = 23.95 g/mol) solution. Hence, its number of moles are calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{30.0 g}{23.95 g/mol}\\= 1.25 mol$

So, volume for LiOH solution is calculated as follows.

$Molarity = \frac{no. of moles}{Volume (in L)}\\2.70 M = \frac{1.25}{Volume}\\Volume = 0.464 L (1 L = 1000 mL)\\= 464 mL$

Therefore, volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.

6 0

2 years ago

500.-liter volume of helium gas is at a pressure of 450 mmHg and has a temperature of 300.K. What is the volume of the same gas

STALIN [3.7K]

Answer:648

Explanation:648

5 0

3 years ago

The molar mass of element X is 42.3 grams per mol and the molar mass for

Drupady [299]

Answer:

X5Y2

Explanation:

% composition of X = 52.2%

% composition of Y = (100 - 52.2) = 47.8%

This means that there are 52.2g of X and 47.8g of Y in the compound

To calculate the empirical formula of the compound, we first convert the gram value to mole value by dividing by their molar masses.

X = 52.2g/42.3g/mol = 1.234mol

Y = 47.8g/96.7g/mol = 0.494mol

Next, we divide each mole value by the smallest value (0.494mol)

X = 1.234mol ÷ 0.494mol = 2.49

Y = 0.494mol ÷ 0.494mol = 1

We multiply each value by 2

X = 2.49 × 2 = 4.98

Y = 1 × 2 = 2

The simple ratio of X:Y is 5:2, hence, their empirical formula is X5Y2.

7 0

2 years ago

Is ammonia a compound or an element?

shutvik [7]

A ammonia is a compound

8 0

2 years ago

A machine increase the rate of doing ______.

GarryVolchara [31]

Doing work “easier “
Called “ fingerstick”

5 0

2 years ago