All categories

3 years ago

Macronutrients include carbohydrates, proteins, lipids, and _____.

Physics

1 answer:

melamori03 [73]3 years ago

8 0

Macronutrients include carbohydrates, proteins, lipids, and fats.

You might be interested in

At what time of day would you expect the New Moon to rise?

abruzzese [7]

Answer:

At what time of day would you expect the New Moon to rise?

A) Midnight

B) Sunset

C) Noon

D) Sunrise

An HR diagram is a plot of:

A) Luminosity versus apparent magnitude.

B) Absolute magnitude versus luminosity.

C) Absolute magnitude versus surface temperature.

D)Apparent magnitude versus color index.

E) Color index versus surface temperature.

What is the most easily visible manifestation of the Earth's magnetic field?

A) The Van Allen radiation belts

B) The magnetopause

C) The aurorae

D) There is no easily visible manifestation of the Earth's magnetic field.

For a lunar eclipse (the moon is obscured from view), which phase is necessary?

A) third quarter

B) new moon

C) first quarter

D) full moon

4 0

3 years ago

Satellite A orbits a planet at a distance d from the planet’s center with a centripetal acceleration a0. A second identical sate

leva [86]

To solve this problem it is necessary to use the concepts related to the Gravitational Force and Newton's Second Law, as far as we know:

$F_g = \frac{GMm}{r^2}$

Where,

G = Gravitational constant

M = Mass of earth (in this case)

m = mass of satellite

r = radius

In the other hand we have the second's newton law:

$F = ma$

Where,

m = mass

a = acceleration

Equation both equations we have,

$ma = \frac{GMm}{r^2}$

For the problem we have that,

Satellite A:

$ma_A = \frac{GMm}{r^2}$

Satellite B:

$ma_B = \frac{GMm}{(2r)^2}$

The ratio between the two satellites would be,

$\frac{ma_A}{ma_B}= \frac{\frac{GMm}{r^2}}{\frac{GMm}{(2r)^2}}$

Solving for a_B,

$a_B = \frac{a_A}{4}$

Therefore the centripetal acceleration of $A_B$ is a quarter of $a_A$

7 0

3 years ago

How can electric shock be prevented?

Nina [5.8K]

Wearing rubber or stay away from water or/ and a conductor

7 0

3 years ago

2 76 Consider a household that uses 14,000 kWh of elec- (tricity per year and 3400 L of fuel oil during a heating sea- son. The

NNADVOKAT [17]

Answer:

The total amount of CO₂ produced will be = 20680 kg/year

The reduction in the amount of CO₂ emissions by that household per year = 3102 kg/year

Explanation:

Given:

Power used by household = 14000 kWh

Fuel oil used = 3400 L

CO₂ produced of fuel oil = 3.2 kg/L

CO₂ produced of electricity = 0.70 kg/kWh

Now, the total amount of CO₂ produced will be = (14000 kWh × 0.70 kg/kWh) + (3400 L × 3.2 kg/L)

⇒ The total amount of CO₂ produced will be = 9800 + 10880 = 20680 kg/year

Now,

if the usage of electricity and fuel oil is reduced by 15%, the reduction in the amount of the CO₂ emission will be = 0.15 × 20680 kg/year = 3102 kg/year

6 0

4 years ago

At t=0 a grinding wheel has an angular velocity of 20.0 rad/s . it has a constant angular acceleration of 34.0 rad/s2 until a ci

natta225 [31]

Let's break the problem into two parts:

1) In the first part, the wheel starts with an angular speed $\omega_0 = 20.0 rad/s$ and it rotates with an angular acceleration of $\alpha_0 = 34.0 rad/s^2$ for t=1.80 s. So we can find the total angle covered by the wheel in this part of the motion:
$\theta(t) = \omega_0 t + \frac{1}{2} \alpha_0 t^2 = 91.1 rad$

2) Now, the circuit breaker trips, so the wheel starts to decelerate with a certain angular acceleration $\alpha_1$ (which is negative). During this part of the motion, the wheel covered an angle of $435 rad$ .

3) So, we just need to add the angles the wheel covered in the two parts of the motion:
$\theta _{tot}=91.1 rad+435 rad=526.1 rad$

6 0

3 years ago