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Artemon [7]
3 years ago
8

How many molecules are in 54.0 grams of CO2?

Chemistry
1 answer:
mote1985 [20]3 years ago
6 0

Answer:

7.38654 in 54 grams

Explanation:

To get moles, you divide grams of a substance by molecular weight. The molecular weight of CO2 is 44 g/mol. 54g divided by 44/mol  is 1.227moles.

You then need to multiply moles by Avogadro’s constant (6.022x10^23). That gives you 7.38654x10^23 molecules in 54 grams of CO2.

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CuSO^4 is an example of a(n)_____.
GarryVolchara [31]

Answer:

Compound.

Explanation:

That would be compound as it consists of a number of elements bonded together.  It is inorganic not organic.

3 0
3 years ago
Aluminum has a density of 2.70 g/mL. Calculate the mass (in grams) of a piece of aluminum having a volume of 264 mL .
gavmur [86]
The formula for density is:

D = m/v

We can use the formula to figure out the mass because we already know two of the three values (we are given the density and volume), so we only have to solve for <em>m. </em>If we plug our given values into the formula, we get:

2.70 = m / 264

Now, all we need to do is solve for <em>m</em>. The goal is to get <em>m</em> on one side of the equation, and all we have to do is multiply each side of the equation by 264:

264 × 2.70 = (m÷264) × 264

264 × 2.70 = m

m = 712.8

The mass of the piece of aluminum is 712.8 grams.
4 0
3 years ago
Difference between pure and applied research
nata0808 [166]

Answer:

pure is water made by us

Explanation:

lap water are pured also but somtimes they are dirty

6 0
2 years ago
Read 2 more answers
Can you light diamond on fire?
Svet_ta [14]

Answer:

Diamond can indeed be set on fire since it is made of carbon. ... You can even burn diamond in a regular flame if you are patient and conditions are right. To accelerate the burning of diamond, you can give it more heat and more oxygen.

Explanation:

4 0
3 years ago
A 0.25-mol sample of a weak acid with an unknown Pka was combined with 10.0-mL of 3.00 M KOH, and the resulting solution was dil
Masteriza [31]

Answer : The value of pK_a of the weak acid is, 4.72

Explanation :

First we have to calculate the moles of KOH.

\text{Moles of }KOH=\text{Concentration of }KOH\times \text{Volume of solution}

\text{Moles of }KOH=3.00M\times 10.0mL=30mmol=0.03mol

Now we have to calculate the value of pK_a of the weak acid.

The equilibrium chemical reaction is:

                          HA+KOH\rightleftharpoons HK+H_2O

Initial moles     0.25     0.03        0

At eqm.    (0.25-0.03)   0.03      0.03

                     = 0.22

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[HK]}{[HA]}

Now put all the given values in this expression, we get:

3.85=pK_a+\log (\frac{0.03}{0.22})

pK_a=4.72

Therefore, the value of pK_a of the weak acid is, 4.72

7 0
3 years ago
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