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3 years ago

How many molecules are in 54.0 grams of CO2?

Chemistry

1 answer:

mote1985 [20]3 years ago

6 0

Answer:

7.38654 in 54 grams

Explanation:

To get moles, you divide grams of a substance by molecular weight. The molecular weight of CO2 is 44 g/mol. 54g divided by 44/mol is 1.227moles.

You then need to multiply moles by Avogadro’s constant (6.022x10^23). That gives you 7.38654x10^23 molecules in 54 grams of CO2.

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What is the name of the gas law relating pressure and volume at a<br> constant temperature?

pochemuha

Answer:

Charles Law

Explanation:

Charles's law (also known as the law of volumes) is an experimental gas law that describes how gases tend to expand when heated. A modern statement of Charles's law is: This relationship of direct proportion can be written as: V∝T

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4 years ago

A 50.0 mL sample of a 1.00 M solution of CuSO4 is mixed with 50.0 mL of 2.00 M KOH in a calorimeter. The temperature of both sol

Reika [66]

Answer : The enthalpy change for the process is 52.5 kJ/mole.

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the solution

$q=[q_1+q_2]$

$q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]$

where,

q = heat released by the reaction

$q_1$ = heat absorbed by the calorimeter

$q_2$ = heat absorbed by the solution

$c_1$ = specific heat of calorimeter = $12.1J/^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_2$ = mass of water or solution = $Density\times Volume=1/mL\times 100.0mL=100.0g$

$\Delta T$ = change in temperature = $T_2-T_1=(26.3-20.2)^oC=6.1^oC$

Now put all the given values in the above formula, we get:

$q=[(12.1J/^oC\times 6.1^oC)+(100.0g\times 4.18J/g^oC\times 6.1^oC)]$

$q=2623.61J$

Now we have to calculate the enthalpy change for the process.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat released = 2626.61 J

n = number of moles of copper sulfate used = $Concentration\times Volume=1M\times 0.050L=0.050mole$

$\Delta H=\frac{2623.61J}{0.050mole}=52472.2J/mole=52.5kJ/mole$

Therefore, the enthalpy change for the process is 52.5 kJ/mole.

8 0

3 years ago

What is Chemistry????

prisoha [69]

Answer:

Chemistry is the scientific study of matter and its properties

Explanation:

hope it helps <3

mark me as brainliest

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2 years ago

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The empirical formula of a hydrocarbon (compound that contains only C and H is found to be CH. laboratory procedures have found

gulaghasi [49]

Answer:

C₆H₆

Explanation:

Molar mass of the compound is 78g/mol

Unknown:

Molecular formula of the compound = ?

Solution:

The empirical formula of the compound is CH.

Empirical formula is the simplest formula of a compound.

To solve this problem:

Find the molar mass of CH;

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Multiplication index = $\frac{78}{13}$ = 6

So;

(CH)₆ ;

Therefore:

C₆H₆

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3 years ago

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3 years ago

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