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Artemon [7]
3 years ago
8

How many molecules are in 54.0 grams of CO2?

Chemistry
1 answer:
mote1985 [20]3 years ago
6 0

Answer:

7.38654 in 54 grams

Explanation:

To get moles, you divide grams of a substance by molecular weight. The molecular weight of CO2 is 44 g/mol. 54g divided by 44/mol  is 1.227moles.

You then need to multiply moles by Avogadro’s constant (6.022x10^23). That gives you 7.38654x10^23 molecules in 54 grams of CO2.

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Which of the following is NOT an acceptable unit for reporting gas pressure?
Arada [10]

Answer:

mL

Explanation:

Atmospheres (atn), Torr, and mm of Hg are all units of pressure but mL is a unit of volume, not pressure.

5 0
3 years ago
A student balances the following redox reaction using half-reactions.
ICE Princess25 [194]
Answer: 6.

Explanation:

1) Aluminum

Al^0-3e^----\ \textgreater \ Al^{3+}

So each atom of aluminum lost 3 electrons to pass from 0 oxidation state to 3+ oxidation state.

2) Manganesium

Mn^{2+}+2e^{-}---\ \textgreater \ Mn

So, each ion of Mn(2+) gained 2 electrons pass from 2+ oxidation state to 0.

3) Balance

Multiply aluminum half-reaction (oxidation) by 2 and multiply manganesium half-raction (reduction) by 3:

2Al^{0}-6e^{-}---\ \textgreater \ 2Al^{3+}

3Mn^{2+}+6e^{-}---\ \textgreater \ 3Mn^{0}

4) Net equation

Add the two half-equations:

2Al^{0}+3Mn^{2+}----\ \textgreater \ 2Al^{3+}+3Mn^{0}

As you see the left side has 2 Al, 3Mn, and 3*2 positive charges.

The right side has 2 Al, 3 Mn, and 2*3 positive charges.

So, the equation is balanced.

5) Count the number of electrons involved.

As you see 2 atoms of aluminum lost 6 electrons (3 each).

That is the answer to the question. 6 electrons will be lost.
5 0
3 years ago
Read 2 more answers
Give reason brick is a solid
Elenna [48]
The brick is solid because it's not hollow or containing spaces or gaps
3 0
3 years ago
(14.1.50) 0.03 mol of helium are enclosed in a cylinder with a piston which maintains a constant pressure in the helium. Initial
icang [17]

Answer:

a) 0.210 j /k

b) 0.032 j/k

Explanation:

Find the attachment for solution

3 0
3 years ago
How many atoms of gold are in gold nugget with a mass of 4.25 g
Feliz [49]
Number of Atoms in Gold for given mass can be calculated using following formula,

              # of Moles  =  Number of Atoms / 6.022 × 10²³
Or,
             Number of Atoms  =  Moles × 6.022 × 10²³     ------- (1)    

Calculating Moles,
As,
                              Moles  =  Mass / M.mass
So,
                              Moles  =  4.25 g / 196.96 g/mol

                              Moles  =  0.0215

Putting value of mole in eq.1,

             Number of Atoms  =  0.0215 × 6.022 × 10²³

             Number of Atoms  =  1.299 × 10²²

Result:
            4.25 g 
of Gold Nugget contains 1.299 × 10²² Atoms.
3 0
3 years ago
Read 2 more answers
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