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Charra [1.4K]
2 years ago
6

In the problems below, f(x) = log2x and g(x) = log10x. How are the graphs of f and g similar? Check all that apply. Both have a

y-intercept of 1. Both increase from left to right. Both have an asymptote of x = 0. Both have a domain of all real numbers.
Chemistry
2 answers:
7nadin3 [17]2 years ago
6 0

Answer:

log x=0 , this is not a sure answer but i hope it works

jeka57 [31]2 years ago
3 0

Answer:

<em>The correct answers are: Both increase from left to right.</em>

<em>Both have an asymptote of x = 0.</em>

Explanation:

<em>Edge 2021.</em>

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Please dont answer if you dont know.​<br>It's the parts of a wave
Marina86 [1]
Answer:

1) wavelength
2) trough
3) amplitude
4) crest

Explanation:

Hope this helps!
5 0
3 years ago
Imagine mixing 1 tablespoon of Epsom salt with 2 cups of ammonia. How much precipitate would be produced? Describe the amount of
iVinArrow [24]

Answer:

https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=1&ved=2ahUKEwjkwv-cqrjnAhVCheAKHWaFBBgQFjAAegQICBAB&url=https%3A%2F%2Fwww.acs.org%2Fcontent%2Fdam%2Facsorg%2Feducation%2Fresources%2Fk-8%2Finquiryinaction%2Fstudent-activity-sheets%2Fgrade-5%2Fchapter-3%2Flesson-3.3-forming-a-precipitate.pdf&usg=AOvVaw1fT7fpXG9PNWroM87puvgQ

Explanation:

that has the answers copy and paste it in your google

6 0
3 years ago
5)
Kryger [21]

The empirical formula : C₁₂H₄F₇

The molecular formula : C₂₄H₈F₁₄

<h3>Further explanation</h3>

mol C (MW=12 g/mol)

\tt \dfrac{18.24}{12}=1.52

mol H(MW=1 g/mol) :

\tt \dfrac{0.51}{1}=0.51

mol F(MW=19 g/mol)

\tt \dfrac{16.91}{19}=0.89

mol ratio of C : H : O =1.52 : 0.51 : 0.89=3 : 1 : 1.75=12 : 4 : 7

Empirical formula : C₁₂H₄F₇

(Empirical formula)n=molecular formula

( C₁₂H₄F₇)n=562 g/mol

(12.12+4.1+7.19)n=562

(281)n=562⇒ n =2

Molecular formula : C₂₄H₈F₁₄

6 0
3 years ago
Here is a more complex redox reaction involving the dichromate ion in acidic solution: 3N O 2 − + 8H + + C r 2 O 7 2− → 3N O 3 −
Fantom [35]

Answer:

NO2- is the reducing agent.

Cr2O7_2- is the oxidizing agent.

H+ is neither

Explanation:

Reduction is the gain in electron. A chemical specie that undergoes reduction is called the oxidizing agent.

Oxidation is simply the loss in electrons. A chemical specie that undergoes oxidation is called the reducing agent.

Let us look at the species.

The first specie is the NO2-. In this specie, the oxidation number of nitrogen changed from +3 to +5 in NO3-. Thus we can see that there is more loss of electron to have caused an increase in the oxidation number positively. This shows an oxidation. Hence, NO2- is the reducing agent.

Let us look at the chromium. We can see that the oxidation number of chromium changed from +7 to +3.

Now we can see that it is a decrease and hence, it is a gain of electron and thus it is reduction. This means the first chromium specie is the oxidizing agent.

The hydrogen ion is simply placed there to balance the ions and hence it is neither the oxidizing nor the reducing agent.

4 0
3 years ago
3.<br> КОН<br> +<br> —<br> —<br> Н3РО4<br> 1<br> +<br> K3PO4<br> —<br> Н,0<br> —
expeople1 [14]
What does this mean?
3 0
2 years ago
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