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Charra [1.4K]
3 years ago
6

In the problems below, f(x) = log2x and g(x) = log10x. How are the graphs of f and g similar? Check all that apply. Both have a

y-intercept of 1. Both increase from left to right. Both have an asymptote of x = 0. Both have a domain of all real numbers.
Chemistry
2 answers:
7nadin3 [17]3 years ago
6 0

Answer:

log x=0 , this is not a sure answer but i hope it works

jeka57 [31]3 years ago
3 0

Answer:

<em>The correct answers are: Both increase from left to right.</em>

<em>Both have an asymptote of x = 0.</em>

Explanation:

<em>Edge 2021.</em>

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A slice of Swiss cheese contains 41 mg of sodium.
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Answer:

a. 41 mg equals 0.041 grams.

b. 41 mg equals 0.0014462 ounces

c. 41 mg equals 9.039*10⁻⁵ pounds

Explanation:

You know that a slice of Swiss cheese contains 41 mg of sodium.

a. What is this mass in grams?

Knowing that 1 mg = 10⁻³ g, you can apply the following rule of three: if 1 mg equals 10⁻³ g or 0.001 grams, 41 mg will be equivalent to how much mass in g?

mass=\frac{41 mg*0.001 g}{1 mg}

mass= 0.041 grams

<u><em> 41 mg equals 0.041 grams.</em></u>

b. What is this mass in ounces?

Knowing that 1 mg = 3.5274 * 10⁻⁵ ounces, you can apply the following rule of three: if 1 mg equals 3.5274 * 10⁻⁵ ounces, 41 mg will be equivalent to how much mass in ounces?

mass=\frac{41 mg*3.5274*10^{-5}ounces }{1 mg}

mass= 1.4462*10 ⁻³ ounces= 0.0014462 ounces

<u><em>41 mg equals 0.0014462 ounces</em></u>

c. What is this mass in pounds?

Knowing that 1 mg = 2.20462 * 10⁻⁶ pounds, you can apply the following rule of three: if 1 mg equals 2.20462 * 10⁻⁶ pounds, 41 mg will be equivalent to how much mass in pounds?

mass=\frac{41 mg*2.20462*10^{-6}pounds }{1 mg}

mass= 9.039*10⁻⁵ pounds

<u><em>41 mg equals 9.039*10⁻⁵ pounds</em></u>

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