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2 years ago

3. If a polynomial equation p(x) = 0 has 3 + 4i as a solution, what other solutions must it have?

Mathematics

2 answers:

GenaCL600 [577]2 years ago

7 0

Answer:

Option (d) is correct.

For the given polynomial p(x) if 3 +4i is a root then, 3 - 4i is also the root of p(x).

Step-by-step explanation:

Consider the given polynomial equation p(x) = 0

It is given that the polynomial P(x) has one root 3 + 4i

According to Complex conjugate theorem , if V is a polynomial and x + iy is a root of given polynomial then its conjugate x - iy is also the root of the polynomial.

Thus, for the given polynomial p(x) if 3 +4i is a root then, 3 - 4i is also the root of p(x).

Thus, option (d) is correct.

True [87]2 years ago

6 0

It must have di 3-4 I as another solution

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Wewaii [24]

Answer:

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Step-by-step explanation:

Given that:

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Thus,

$P(x)$ ÷ $Q(x)$ = $\frac{2}{3x - 1}$ ÷ $\frac{6}{-3x + 2}$

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Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

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$\frac{-6x + 18x + 4 - 6}{(3x - 1)(-3x + 2)}$

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$\frac{-6x - 18x + 4 + 6}{(3x - 1)(-3x + 2)}$

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Step-by-step explanation:

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