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Olin [163]
3 years ago
5

3. If a polynomial equation p(x) = 0 has 3 + 4i as a solution, what other solutions must it have?

Mathematics
2 answers:
GenaCL600 [577]3 years ago
7 0

Answer:

Option (d) is correct.

For the given polynomial p(x)  if 3 +4i is a root then, 3 - 4i is also the root of p(x).

Step-by-step explanation:

Consider the given polynomial equation p(x) = 0

It is given that the polynomial P(x) has one root 3 + 4i

According to Complex conjugate theorem ,  if V is a polynomial and x + iy is a root of given polynomial then  its conjugate x - iy is also the root of the polynomial.

Thus, for the given polynomial p(x)  if 3 +4i is a root then, 3 - 4i is also the root of p(x).

Thus, option (d) is correct.

True [87]3 years ago
6 0
It must have di 3-4 I as another solution
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Answer:

Step-by-step explanation:

From Bayes' theorem is stated mathematically as the following equation:[2]

{\displaystyle P(A\mid B)={\frac {P(B\mid A)\,P(A)}{P(B)}},}

where A and B are events and P(B) ≠ 0.

P(A) and P(B) are the probabilities of observing A and B without regard to each other.

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At this point, go through the attached file before you continue with part B.

Part B)

P(silver) = P(silver from SS)+P(silver from GS)

note P(SS)=P(GG)=P(GS) = 1/3

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hence

P(Silver from SS) = 1/3

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4 0
3 years ago
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Answer:

a

Step-by-step explanation:

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