If the endpoints of a diameter are (6,3) and (2,1) the midpoint is the center of the circle so:
(x,y)=((6+2)/2, (3+1)/2)=(4,2)
Now we need to find the radius....the diameter is:
d^2=(6-2)^2+(3-1)^2
d^2=16+4
d^2=20 since d=2r, r=d/2, and r^2=d^2/4 so
r^2=5
The standard form of the circle is (x-h)^2+(y-k)^2=r^2 and we know:
(h,k)=(4,2) from earlier so:
(x-4)^2+(y-2)^2=5
Answer: X=3,1
The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace y with 0 and solve for x
Step-by-step explanation: Have a nice day
Answer:
Step-by-step explanation:
Andrew made a mistake at last step.
<u>It should be:</u>
- -11.8 + 9.8 = 9.8 - 11.8 = -2 but not -21.6
No. 43 is a prime number. It has no other factors besides ' 1 ' and itself.