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3 years ago

Which of the following statements describes an interaction between the geosphere and atmosphere?

Physics

2 answers:

german3 years ago

8 0

B is the answer, I’m really good at this subject

Misha Larkins [42]3 years ago

4 0

Answer:

Option (A)

Explanation:

Wind is created due to the pressure difference and it blows from a region of higher pressure to a region of low pressure.

Atmosphere refers to the envelope of gases that surrounds the earth. It is comprised of various types of gases which are present in various amount.

The wind blowing away sand in a desert environment describes the interaction between the geosphere and the atmosphere as the wind is a part of the atmosphere and the sand is a part of the geosphere.

Hence, the correct answer is option (A).

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5. A person fishing from a pier observes that four wave crests pass by in 7.0 s and estimates that the distance between two succ

TiliK225 [7]

Answer:

v= 1.71 m/s

Explanation:

Given that

Distance between two successive crests = 4.0 m

λ = 4 m

T= 7 sec

T is the time between 3 waves.

3 waves = 7 sec

1 wave = 7 /3 sec

So t= 7/3 s

We know that frequency f

f= 1/t= 3/7 Hz

Lets take speed of the wave is v

v= f λ

f=frequency

λ=wavelength

v= 3/7 x 4 = 12 /7

v= 1.71 m/s

3 0

3 years ago

An oxygen atom can absorb any frequency of light to cause its electrons to increase in energy.

sashaice [31]

Answer:

that's true.

Explanation:

that's the reason why oxygen supports burning.

8 0

2 years ago

A 25,000 kg traveling east collides with a 2,000 kg truck standing still on the tracks. After the collision the train and truck

Elis [28]

Answer:

24.084 m/s

Explanation:

From the law of conservation of linear momentum

Total momentum before collision equals to the total momentum after collision

Since momentum=mv where m is mass and v is velocity

$M_{truck}V_{truck}=V_{common}*(M_{truck} +M_{standing})$ where $M_{truck}$ is the mass of the truck, $V_{truck}$ is velocity of the truck, $V_{common}$ is the common velocity of moving and standing truck after collision and $M_{standing}$ is the mass of the standing truck

Making $V_{truck}$ the subject we obtain

$V_{truck}=\frac { V_{common}*(M_{truck} +M_{standing})}{M_{truck}}$

Substituting $M_{truck}$ as 25000 Kg, $V_{common}$ as 22.3 m/s, $M_{standing}$ as 2000 Kg we obtain

$V_{truck}=\frac { 22.3 m/s *(25000 Kg +2000 Kg)}{25000}= 24.084 m/s$

Therefore, assuming no friction and considering that after collision they still move eastwards hence common velocity and initial truck velocities are positive

The truck was moving at 24.084 m/s

3 0

3 years ago

You and your friend are both 14 years old. Your friend however moves to a planet where just 30 minutes on that planet is the sam

vaieri [72.5K]

Answer:

ok so

Explanation:

1.) 1 hour

2.) 14 years old

3.)

24 years old

4.) you are

5 0

2 years ago

A spherical balloon with radius r inches has volume V(r) = 4 3 πr3. Find an expression that represents the amount of air require

DerKrebs [107]

So the question ask to formulate an expression to represent the amount of air required to inflate the balloon from a radius of R+4 and the expression would be V=16pi/3*(3r^2+12r+16). I hope you are satisfied with my answer and feel free to ask for more if you have question and further clarifications

4 0

3 years ago