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djverab [1.8K]
3 years ago
6

The following steps occur in rods when they are excited by photons of light. What is the proper sequence for these steps? 1. Mem

brane sodium channels close. 2. Increased phosphodiesterase breaks down cGMP. 3. Retinal changes from the 11-cis form to the 11-trans form. 4. The membrane hyperpolarizes and the rate of neurotransmitter release declines. 5. Opsin activates transducin. 6. Opsin activation occurs.
Physics
1 answer:
RSB [31]3 years ago
3 0

Answer: 1, 6, 5, 2, 4, 3

Explanation:

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Two red blood cells each have a mass of 9.0 × 10 − 14 kg and carry a negative charge spread uniformly over their surfaces. The r
Gennadij [26K]

Answer:

321.39 m/s

1.3772213803 \times 10^{10}\ m/s^2

Explanation:

m = Mass = 9\times 10^{-14}\ kg

q_1 = Charge = -2.50 pC

q_2 = Charge = -3.10 pC

r = Radius = 3.75 μm

\varepsilon_{0} = Vacuum permittivity = 8.85 \times 10^{-12}\ F/m

We have the relation

m v^{2} &=\frac{q_{1} q_{2}}{4 \pi \varepsilon_{0} 2 r}

v =\sqrt{\frac{q_{1} q_{2}}{4 \pi \varepsilon_{0}(2 r)(m)}}

=\sqrt{\frac{\left(-2.50 \times 10^{-12}\right)\left(-3.1 \times 10^{-12}\right)}{4(3.14)\left(8.85 \times 10^{-12}\right)\left(2 \times 3.75 \times 10^{-6}\right)\left(9 \times 10^{-14}\right)}}

=321.39\ m/s

The Speed they need when very far away from each other to get close enough to just touch is 321.39 m/s

We have the relation

m a=\frac{q_{1} q_{2}}{4 \pi \varepsilon_{0}(2 r)^{2}}

a=\frac{q_{1} q_{2}}{4 \pi \varepsilon_{0}(2 r)^{2}(m)}

=\frac{\left(-2.50 \times 10^{-12}\right)\left(-3.10 \times 10^{-12}\right)}{4(3.14)\left(8.85 \times 10^{-12}\right)\left(2 \times 3.75 \times 10^{-6}\right)^{2}\left(9 \times 10^{-14}\right)}

a=1.3772213803 \times 10^{10} \mathrm{m} / \mathrm{s}^{2}

The acceleration is 1.3772213803 \times 10^{10}\ m/s^2

8 0
3 years ago
A hockey puck initially travelling to the right at 34 m/s. It moves for 7 before
goldfiish [28.3K]

Answer:

x=119m

Explanation:

Hello,

In this case, since the hockey puck was moving at 34 m/s and suddenly stopped (final velocity is zero) in 7 seconds, we can first compute the acceleration via:

a=\frac{v_f-v_o}{t}=\frac{0m/s-34m/s}{7s}\\  \\a=-4.86m/s^2

In such a way, we can compute the displacement via:

x=\frac{v_f^2-v_o^2}{2a}\\ \\x=\frac{0^2-(34m/s)^2}{2*-4.86m/s^2}\\ \\x=119m

Best regards.

3 0
3 years ago
Two speakers separated by a distance of 4.40 m emit sound. The speakers have opposite phase. A person listens from a location 3.
Hoochie [10]

Answer:

f = 147.21 Hz

Explanation:

In order to have a destructive interference, as the source emit in opposite phases, the path difference between the distance to the person, measured in a straight line from the speakers, must be equal to an integer number of wavelengths.

We need to know the distance from the listener to the other speaker, located 4.4 m from the one which is directly in front of him, which we can find using Pythagorean theorem, as follows:

l₂ = √(3)²+(4.4)² = 5.33 m

The difference in path will be, then:

d = l₂-l₁ = 5.33 m - 3.00 m = 2.33 m

For the lowest frequency that gives destructive interference, the wavelength will be highest possible, which happens when the distance is just one wavelength.

⇒ d = λ = 2.33 m

In any wave, there exists a fixed relationship between speed, frequency and wavelength, as follows:

v = λ*f Κ  ⇒ f = v/λ

Taking the speed of sound as 343 m/s, and solving for f, we get:

f= 343 m/s / 2.33 m = 147.21 Hz

3 0
3 years ago
Suppose the activity of a sample of radioactive material was 100Bq at the start. What would you divide 100Bq by to obtain the ac
myrzilka [38]
If n=1 you divide by 2
If n=2 you divide by 4
If n=3 you divide by 8
so any n you divide by 2 to the power n
4 0
3 years ago
12)
Nataliya [291]

Answer: b

Explanation: the two pieces will repel as both have obtained a static charge.

5 0
3 years ago
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