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sladkih [1.3K]
3 years ago
14

A first-order reaction has a rate constant of 0.241/min. if the initial concentration of a is 0.859 m, what is the concentration

of a after 10.0 minutes?
Physics
2 answers:
nordsb [41]3 years ago
5 0

Answer: 0.077 M

Explanation:

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant = 0.241minute^{-1}

t = time taken for decay process = 10 minutes

a = initial amount of the reactant= 0.859 M

a - x = amount left after decay process =?

Putting values in above equation, we get:

0.241 minutes^{-1}=\frac{2.303}{10.0}\log\frac{0.859}{a-x}

(a-x)=0.077M

Thus the concentration of a after 10.0 minutes is 0.077 M.


Juli2301 [7.4K]3 years ago
3 0
Initial concentration is 0.859 m.
A rate: 0.241 m/min.
In 10 minutes: 10 min * 0.241 m/min = 2.41 m
0.859 m + 2.41 = 3.269 m
Answer: After 10 minutes the concentration is 3.269 m. 
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