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3 years ago

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Question 5 of 10

1 answer:

jonny [76]3 years ago

4 0

Answer:

A. The particle model, because only high-energy frequencies of light can remove electrons .

Explanation:

Each photon of blue light has higher energy than each photon of red light has . So when each photon strikes each electron , it gets ejected . But the photon of red light has not sufficient energy to eject electron . Once the photon of red light strikes the electron , the energy is wasted off . Energy of photon can not be accumulated . Thus photon behaves like particle .

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Disadvantages of friction

MrRa [10]

Heat, kinetic energy loss.

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2 years ago

A nation undergoing the transition from undeveloped to industrialized is commonly dependent on this to supply its energy needs.

algol [13]

A) obviously :)))))))))

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2 years ago

Read 2 more answers

Question 1 of 10

Novay_Z [31]

Answer:

C. 5.6 × 10^11 N/C

Explanation:

The electric field $E$ at a distance $R$ from a charge $Q$ is given by

$E = k\dfrac{Q}{R^2}$

where $k = 9*10^9Nm/C$ is the coulomb's constant.

Now, in our case

$R = 0.0075m$

$Q = 0.0035C$ ;

therefore,

$E = (9*10^9)\dfrac{0.0035C}{(0.0075m)^2}$

$\boxed{E = 5.6*10^{11}N/C.}$

which is choice C from the options given<em> (at least it resembles it).</em>

6 0

3 years ago

What is the wavelength of a sound wave<br> with a speed of 331 m/s and a frequency<br> of 500 Hz?

ludmilkaskok [199]

Answer:

0.777m

Explanation:

The sound wave has a wavelength of 0.773m.

Explanation:

To solve this problem we have to use the wave equation that is given below:

We know the frequency and the velocity, both of which have good units. All we have to do is rearrange the equation and solve for

λ :

λ = v f

Let's plug in our given values and see what we get!

λ = 340 m s

440 s − 1

λ = 0.773 m

Hope this helps, Mark as brainliest if u want

4 0

2 years ago

Initially (at time t = 0) a particle is moving vertically at 7.5 m/s and horizontally at 0 m/s. Its horizontal acceleration is 1

Lelu [443]

Answer:

t = 0.657 s

Explanation:

given,

initial vertical velocity = 7.5 m/s

initial horizontal velocity = 0 m/s

angle = 49◦

using kinetic equation

final velocity in vertical direction

v sinθ = u_y - gt ........................(1)

final velocity in horizontal direction

v cosθ = u_x + a_x × t

here u_x = 0.0 m/s

v cosθ = a_x×t ......................(2)

Dividing equation (1) / (2)

$tan \theta =\dfrac{u_y - gt}{a_x\times t}$

solving for time t

$t = \dfrac{u_y}{tan \theta \times a_x + g}$

u_y = initial velocity along x direction

acceleration along a_x = 1.4 m/s²

g = acceleration due to gravity = 9.8 m/s²

θ = 43° , u_y = 7.5 m/s

$t = \dfrac{7.5}{tan 49^0\times 1.4+ 9.8}$

t = 0.657 s

time taken by the particle is t = 0.657 s

6 0

2 years ago