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3 years ago

6. Anna can walk 10 miles in 4 hours. At this rate, how many minutes does it take her to walk one mile?

Mathematics

2 answers:

Slav-nsk [51]3 years ago

8 0

Answer:

150 minutes

Step-by-step explanation:

10/4 divided by 4/4 is 2.5/4

2.5 hours = 150 minutes

Licemer1 [7]3 years ago

4 0

Answer:

24 minutes, I got this by :

4x60=240 divided by 10 = 24

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The fifth graders are planning a pizza party. Each fifth grader will eat two slices of pizza with a favorite topping. One-half o

icang [17]

32 students choose a favorite topping for their slices.

Let x be the total number of students.

1/2 of the total students, or 1/2x, choose pepperoni.
1/4 of the total students, or 1/4x, choose extra cheese.
1/8 of the total students, or 1/8x, choose sausage.
4 students choose mushrooms.

We know that together, these equal the total number of students, x:
1/2x+1/4x+1/8x+4=x

We will use 8 as the common denominator:
4/8x+2/8x+1/8x+4=x

Combining like terms:
7/8x+4=x

Subtract 7/8x from both sides:
7/8x+4-7/8x=x-7/8x
4=1x-7/8x
4=1/8x

Divide both sides by 1/8:
4÷(1/8) = 1/8x÷(1/8)
4/1÷(1/8) = x
4/1×8/1 = x
32/1 = x
32 = x

4 0

3 years ago

What is the value of pi

11111nata11111 [884]

Pi really goes on for infinity, but here are the first seven numbers:

3.14159

8 0

3 years ago

mya has ballet lessons every sixth day and swimming every fourth day. today she has both lessons. in how many days will mya have

ra1l [238]

To determine when Mya will have both lessons again on the same day, you will list the multiples of each number of days because to show every 4 or 6 days, you will count by 4's and 6's.

When you get to the first number that is the same, that will be the next time she will have both lessons again. This is called the least common multiple (LCM).

4, 8, 12, 16, 20, ...
6, 12, 18, 24

In 12 days she will have both lessons again.

5 0

3 years ago

HELP ASAP!! What is angle 1 called??

ololo11 [35]

Your right it’s an obtuse angle

7 0

3 years ago

Match its group with its percentage or mean Using

krok68 [10]

(1)

Mean length of all fish in the sample - $\boxed{\sf{\red{6.2}}}$

Mean = (Sum of observations)/(Number of observations)

= (12 + 5 + 3 + 5 + 8 + 2 + 10 + 9 + 4 + 4)/(10)

= 62/10

= 6.2

(2)

Mean length of adult fish in the sample - $\boxed{\sf{\red{8.75}}}$

Mean = (Sum of observations)/(Number of observations)

= (12 + 5 + 8 + 10)/(4)

= 35/4

= 8.75

(3)

Mean length of juvenile fish in the sample - $\boxed{\sf{\red{4.5}}}$

Mean = (Sum of observations)/(Number of observations)

= (5 + 3 + 2 + 9 + 4 + 4)/(6)

= 27/6

= 4.5

(4)

Percentage of sample that were adult fish - $\boxed{\sf{\red{40}}}$

Percentage = (No. of adult fishes)/(Total no. of fishes) × 100

% = (4/10) × 100

% = 40

(5)

Percentage of sample that were juvenile fish - $\boxed{\sf{\red{60}}}$

Percentage = (No. of juvenile fishes)/(Total no. of fishes) × 100

% = (6/10) × 100

% = 60

(6)

Percentage of sample that were juveniles over 8 inches long - $\boxed{\sf{\red{10}}}$

Percentage = (No. of juveniles over 8 inches)/(Total no. of fishes) × 100

% = (1/10) × 100

% = 10

7 0

3 years ago