The initial concentration was 8.45M
Step 1: Given data
Initial concentration (C₁): ?
Initial volume (V₁): 635 mL = 0.845 L
Final concentration (C₂): 6.00 M
Final volume (V₂): 1.19 L
Step 2: Calculate the initial concentration
We have a concentrated NaCl solution and we want to prepare a diluted one. We will use the dilution rule.
C₁ × V₁ = C₂ × V₂
C₁ = C₂ × V₂ / V₁
C₁ = 6.00 M × 1.19 L / 0.845 L
C₁ = 8.45 M
Thus, The initial concentration was 8.45M
Learn more about concentration here:
brainly.com/question/10725862
#SPJ4
do everything
eh
t
b
b
eh
g
but
b
t
b
43 degrees
angle of reflection is equal to the angle of incidence
Answer:
b. The transmittance of the cuvette must be measured in the same place each time.
Explanation:
When using a spectrophotometer, light passes not only through the liquid sample, it also passes through the cuvette. This means that each time a reading is made, you not only measure the transmittance/absorbance of the sample, <u>but of the cuvette as well</u>.
For this reason it's important that the reading of the cuvette's absorbance remains the same through all the process, so the answer is b), because different faces of the cuvette may have different absorbances.
Answer:
Cation Ca2+
Anion NO3-
Explanation:
Let’s first start with a chemical equation for the reaction.
Ca(OH)2 + 2HNO3 → Ca(NO3)2 + 2H2O.
The name of the compound formed is calcium trioxonitrate V
The Cation there is the positive ion and it Is the calcium ion.
The Anion there is the negative ion and it Is the NO3- ion called trioxonitrate V ion
