All categories

3 years ago

Thomas thinks that acceleration means “speeding up.” Explain why this is incorrect.

2 answers:

8 0

Answer: Thomas is wrong because acceleration is the name we give to any process where the velocity changes. Since velocity is a speed and direction, there are only two ways for you to accelerate: change your speed or change your direction or both.

klemol [59]3 years ago

4 0

Answer:

Explanation:

Thomas is incorrect because acceleration is a vector quantity that is defined as the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity.

You might be interested in

What is the parts of the Transverse wave and longitudinal wave

dexar [7]

Crest, trough, amplitude and wavelength

3 0

3 years ago

On the ph scale, indicate which direction is increasingly acidic and which is increasingly basic.

alexdok [17]

1 2 3 4 5 6 7 8 9 10 11 12 13 14
From 1-6.5 ph acidic
From 7-14 ph alkaline

8 0

3 years ago

When a lithium atom forms an Li+ ion, the lithium atom

gizmo_the_mogwai [7]

4, loses an electron. a plus sign indicates an atom is losing an electron while a minus sign indicates an atom is gaining an electron
hope this helps!

3 0

3 years ago

Read 2 more answers

A student reacts 5.0 g of sodium with 10.0 g of chlorine and collect 5.24 g of sodium chloride. What is the percent yield of thi

Ede4ka [16]

Answer: The percent yield of this combination reaction is 41.3 %

Explanation : Given,

Mass of $Na$ = 5.0 g

Mass of $Cl_2$ = 10.0 g

Molar mass of $Na$ = 23 g/mol

Molar mass of $Cl_2$ = 71 g/mol

First we have to calculate the moles of $Na$ and $Cl_2$ .

$\text{Moles of }Na=\frac{\text{Given mass }Na}{\text{Molar mass }Na}$

$\text{Moles of }Na=\frac{5.0g}{23g/mol}=0.217mol$

and,

$\text{Moles of }Cl_2=\frac{\text{Given mass }Cl_2}{\text{Molar mass }Cl_2}$

$\text{Moles of }Cl_2=\frac{10.0g}{71g/mol}=0.141mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation will be:

$2Na+Cl_2\rightarrow 2NaCl$

From the balanced reaction we conclude that

As, 2 mole of $Na$ react with 1 mole of $Cl_2$

So, 0.217 moles of $Na$ react with $\frac{0.217}{2}=0.108$ moles of $Cl_2$

From this we conclude that, $Cl_2$ is an excess reagent because the given moles are greater than the required moles and $Na$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $NaCl$