The pressure would increase. When the temperature change form cold to hot, the gas will find ways to escape from containment. Thus, if it cannot escape that pressure will keep on increasing as the temperature rises.
Answer:
the mass of the air in the room is 4.96512 kg ( in 0°C)
Answer:
Kc = 50.5
Explanation:
We determine the reaction:
H₂ + I₂ ⇄ 2HI
Initially we have 0.001 molesof H₂
and 0.002 moles of I₂
If we have produced 0.00187 moles of HI in the equilibrium we have to know, how many moles of I₂ and H₂, have reacted.
H₂ + I₂ ⇄ 2HI
In: 0.001 0.002 -
R: x x 2x
Eq: 0.001-x 0.002-x 0.00187
x = 0.00187/2 = 9.35×10⁻⁴ moles that have reacted
So in the equilibrium we have:
0.001 - 9.35×10⁻⁴ = 6.5×10⁻⁵ moles of H₂
0.002 - 9.35×10⁻⁴ = 1.065×10⁻³ moles of I₂
Expression for Kc is = (HI)² / (H₂) . (I₂)
0.00187 ² / 6.5×10⁻⁵ . 1.065×10⁻³ = 50.5
Answer:
Inverse proportion occurs when one value increases and the other decreases. For example, more workers on a job would reduce the time to complete the task. They are inversely proportional.
Answer:
1. Dynamic equilibrium is a equilibrium in which the rate of forward direction is equal to the rate of backward direction. It is represented by a right left arrow.
2) Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as 
For the given chemical reaction:
![Fe^{3+}(aq)+SCN^-(aq)\rightleftharpoons [Fe(SCN)]^{2-}(aq)](https://tex.z-dn.net/?f=Fe%5E%7B3%2B%7D%28aq%29%2BSCN%5E-%28aq%29%5Crightleftharpoons%20%5BFe%28SCN%29%5D%5E%7B2-%7D%28aq%29)
The expression for is written as:
![K_c=\frac{[[Fe(SCN)]^{2-}]}{[Fe^{3+}][SCN^-]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5B%5BFe%28SCN%29%5D%5E%7B2-%7D%5D%7D%7B%5BFe%5E%7B3%2B%7D%5D%5BSCN%5E-%5D%7D)
3) The value of is 1000 , which means the products are more favoured as compared to reactants and that the equilibrium lies more towards product side.
