Answer:
0.57 m
Explanation:
First of all, we need to calculate the time it takes for the ball to cover the horizontal distance between the starting position and the crossbar. This can be done by analzying the horizontal motion only. In fact, the horizontal velocity is constant and it is

And the distance to cover is
d = 19 m
So the time taken is

Now we want to find how high the ball is at that time. The initial vertical velocity is

So the vertical position of the ball at time t is

where g = 9.8 m/s^2 is the acceleration of gravity. Substituting t = 2.04 s, we find

The crossbar height is 3.05 m, so the difference is

So the ball passes 0.57 m above the crossbar.
It is b 9.1 :) have a nice day
Attached a diagram of the scheme described in the problem ..
To solve the problem we need to know the relationship between kinetic and normal force, so

Where
coefficient of kinetic
Normal force
We perform the sum of forces as well,
(2)

For Normal Force in Y,
(3)
The force in X,
(4)
Replacing in (4)




In this way, it does not matter which object is chosen.
Helpful friction would be the friction on something that you wanted to stop (a car) while unhelpful friction is friction on something that you want to keep going (a curling rock)