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gladu [14]
3 years ago
15

Question 1.1. What are the properties of elements related to? (Points : 1)

Physics
1 answer:
laila [671]3 years ago
5 0
The number of electrons that fill the outer shell

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To win the game, a place kicker must kick a
masya89 [10]

Answer:

0.57 m

Explanation:

First of all, we need to calculate the time it takes for the ball to cover the horizontal distance between the starting position and the crossbar. This can be done by analzying the horizontal motion only. In fact, the horizontal velocity is constant and it is

v_x = u cos \theta = (15)(cos 51.7^{\circ})=9.30 m/s

And the distance to cover is

d = 19 m

So the time taken is

t=\frac{d}{v_x}=\frac{19}{9.30}=2.04 s

Now we want to find how high the ball is at that time. The initial vertical velocity is

u_y = u sin \theta = (15)(sin 51.7^{\circ})=11.77 m/s

So the vertical position of the ball at time t is

y(t) = u_y t - \frac{1}{2}gt^2

where g = 9.8 m/s^2 is the acceleration of gravity. Substituting t = 2.04 s, we find

y=(11.77)(2.04)-\frac{1}{2}(9.8)(2.04)^2=3.62 m

The crossbar height is 3.05 m, so the difference is

\Delta h = 3.62 - 3.05 =0.57 m

So the ball passes 0.57 m above the crossbar.

8 0
3 years ago
What causes ray of white light to spilt into seven colors when passed through a prism
saul85 [17]

Dispersion, I think.

3 0
3 years ago
Read 2 more answers
Plz help it’s passed due!
pickupchik [31]
It is b 9.1 :) have a nice day
5 0
3 years ago
You need to design an experiment to measure the free-fall acceleration. You have an inclined plane made of steel and several obj
Nataliya [291]

Attached a diagram of the scheme described in the problem ..

To solve the problem we need to know the relationship between kinetic and normal force, so

F_k=\mu_k F_N (1)

Where

\mu_k = coefficient of kinetic

F_N=  Normal force

We perform the sum of forces as well,

\sum F_x = Ma(2)

a= Acceletarion

For Normal Force in Y,

F_N= Mgcos \theta  (3)

The force in X,

\sum F_x = Mgsin\theta - F_x (4)

Replacing in (4)

Ma = Mgsin\theta - \mu_k F_N

Ma = Mgsin\theta - \mu_k F_N

Ma = Mgsin\theta - \mu_k Mg cos\theta

a= g(sin\theta-\mu_k cos\theta)

In this way, it does not matter which object is chosen.

6 0
3 years ago
What are some examples of helpful and unhelpful frictions?
ladessa [460]
Helpful friction would be the friction on something that you wanted to stop (a car) while unhelpful friction is friction on something that you want to keep going (a curling rock)
8 0
3 years ago
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