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vichka [17]
4 years ago
9

How is thermal energy transferred during convection? by physical contact by electromagnetic waves by movement in fluids by mecha

nical waves
Physics
2 answers:
Alla [95]4 years ago
7 0

by movement in fluids

iris [78.8K]4 years ago
4 0

Answer: by movement in fluids

Explanation:

There are three modes of transfer of thermal energy.

Conduction, convection and radiation.

Transfer of thermal energy via <u>conduction</u> takes place from hotter object and to colder object when they are contact.

Transfer of thermal energy via convection takes place through fluids. The bulk motion of fluids transfers energy.

<u>Radiation </u>transfers thermal energy via space.

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Your little sister is building a radio from scratch. Plans call for a 500 μH inductor wound on a cardboard tube. She brings you
gayaneshka [121]

Answer:

N = 195 turns

Explanation:

The inductance of the inductor, L = 500 μH = 500 * 10⁻⁶H

The length of the tube, l = 12 cm = 0.12 m

The diameter of the tube, d = 4 cm = 0.04 m

Radius, r = 0.04/2 = 0.02 m

Area of the tube, A = πr² = 0.02²π = 0.0004π m²

\mu_{0} = 4\pi * 10^{-7}

The inductance of a solenoid is given by:

L = \frac{\mu_{0}N^{2} A }{l}

500 * 10^{-6} = \frac{4\pi *10^{-7}  N^{2} *4\pi  *10^{-4}  }{0.12}\\500 * 10^{-6} = 0.00000001316N^{2} \\N^{2} = \frac{500 * 10^{-6}}{0.00000001316}\\N^{2} = 37995.44\\N = \sqrt{37995.44} \\N = 194.92 turns

8 0
3 years ago
Please help asap!!!!!!!!!!!
Tomtit [17]
The answer would be 20000

The answer in standard form/scientific notation would be 2 x 10^4

(The exponent is 4 because that's how many digits after the 2 there is)
8 0
2 years ago
Water is poured into a container that has a leak.The
kotykmax [81]
I calculated on a sheet and used differentiation to solve the problems.

5 0
3 years ago
A rigid, insulated tank contains steam at 3 MPa, 400 Celsius. A valve on the tank is opened, allowing steam to escape. The overa
enot [183]

Answer:

x=0.8

Explanation:

Defining our values we have

p_1=3Mpa\\T_1=400\° c\\q_{1-2}=0

Where p_1 is the pressure of the super heated steam

T_1 is the Temperature of the super heated steam

and q_{1-2} is the pressure in an adiabatic process.

State 1

v_1 = 0.09936m^3/Kg\\s_1=6.9213kJ/kg.K

State 2

s_2=s_1=6.9212

Note that here in state 2 the process is Reversible.

At the value where T_2 = 141\°c we have

v_2=(v_g)_{T_2}=0.4972m^3/kg

Through this values we can calculate the Fraction of steam,

x=\frac{m_1-m_2}{m_1}\\x=1-\frac{m_2}{m_1}\\x=1-\frac{v_1}{v_2}\\x=1-\frac{0.9936}{0.4972}\\x=0.8

4 0
3 years ago
Block 1, of mass m1
musickatia [10]

Answer:

M2=0.52kg

Explanation:

thats rightt

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