How are electromagnetic waves different than all the other waves

We measure the loudness of sound in decibels.<br> a. True<br> b. False

Tatiana [17]

Answer: The correct answer is True.

Explanation:

Loudness of sound is referred to how soft or loud a sound is for the listener.

This term is measured in a unit known as decibels referred to as dB.

This unit is used to measure the relative intensity of sounds on a scale from zero to 100 dB.

More the value of decibels, it will be uncomfortable for a person to hear that sound.

So Yes, the loudness of sound is measured in decibels.

7 0

3 years ago

Doctor prescribed drug which is 500mg for patient change this unit into gram

ololo11 [35]

Answer:

.5 grams

Explanation:

1 gram is equal to 1000 milligrams (mg)

6 0

3 years ago

If the sun had twice the mace how would that affect the gravitational force of the sun

daser333 [38]

Answer: Gravity is the force that keeps planets in orbit around the Sun. Gravity alone holds us to Earth's surface.

Planets have measurable properties, such as size, mass, density, and composition. A planet's size and mass determines its gravitational pull.

A planet's mass and size determines how strong its gravitational pull is.

Models can help us experiment with the motions of objects in space, which are determined by the gravitational pull between them.

Explanation:

5 0

3 years ago

If two runners take the same amount of time to run a mile, they have the same __________.

Elan Coil [88]

None of the choices is correct.

If two runners take the same amount of time to run a mile,
they have the same average speed. But their velocities
are not the same unless both runners begin and end their
run at the same points.

Speed is (distance covered) divided by (time to cover the distance).

Velocity is not. It's something different.
'Velocity' is not just a bigger word for 'speed'.

3 0

3 years ago

Read 2 more answers

Help meh in this question plzzz <br>

iragen [17]

The Moment of Inertia of the Disc is represented by $I = \frac{15}{32}\cdot M\cdot R^{2}$ . (Correct answer: A)

Let suppose that the Disk is a Rigid Body whose mass is uniformly distributed. The Moment of Inertia of the element is equal to the Moment of Inertia of the entire Disk minus the Moment of Inertia of the Hole, that is to say:

$I = I_{D} - I_{H}$ (1)

Where:

$I_{D}$ - Moment of inertia of the Disk.

$I_{H}$ - Moment of inertia of the Hole.

Then, this formula is expanded as follows:

$I = \frac{1}{2}\cdot M\cdot R^{2} - \frac{1}{2}\cdot m\cdot \left(\frac{1}{2}\cdot R^{2} \right)$ (1b)

Dimensionally speaking, Mass is directly proportional to the square of the Radius, then we derive the following expression for the Mass removed by the Hole ( $m$ ):