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svp [43]
4 years ago
12

Here is a more complex redox reaction involving the permanganate ion in acidic solution

Chemistry
1 answer:
guapka [62]4 years ago
8 0

Answer:

5NO2? + 6H+ + 2MnO4? ? 5NO3? +2Mn2+ + 3H2O

Explanation:

Classify each reactant as the reducing agent, oxidizing agent, or neither

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If 25.8 grams of BaO dissolve in enough water to make a 212-gram solution, what is the percent by mass of the solution?
Igoryamba
The correct answer is 12.2% BaO.

The solution is found by dividing the mass of the BaO, which is 25.8 grams, by the total mass of the solution, which is 212 grams, then multiplying it by 100 to get the percentage:
\frac{25.8}{212}*(100) =12.2%
3 0
3 years ago
How many grams of water are produced when 2.50 mol oxygen reacts with hydrogen?
natali 33 [55]
I think the answer is D
4 0
3 years ago
Which of the following measurements is equal to 150dL
Eduardwww [97]
Micrometer and millimeter
7 0
3 years ago
Carl walked 12m north then turned around and walked back 4m south. What was his
aleksklad [387]

Answer:

Distance: 16m Displacement: 8m North

Explanation:

Total distance is the total amount traveled, regardless of direction. So, you would just add 12 and 4 to get a total distance of 16m. Displacement is the distance/direction from the start to the end point, regardless of which way you got there. So, to find displacement, you just subtract:

12m North - 4m South = 8m North

** I could be wrong so definitely double check this answer with a similar question**

3 0
3 years ago
Purification of copper can be achieved by electrorefining copper from an impure copper anode onto a pure copper cathode in an el
Dovator [93]

Answer: 406 hours

Explanation:

Q=I\times t

where Q= quantity of electricity in coloumbs

I = current in amperes = 39.5 A

t= time in seconds = ?

The deposition of copper at cathode is represented by:

Cu^{2+}+2e^-\rightarrow Cu

96500\times 2=193000 Coloumb of electricity deposits 1 mole of copper

i.e. 63.5 g of copper is deposited by = 193000 Coloumb

Thus 19.0 kg or 19000 g of copper is deposited by = \frac{193000}{63.5}\times 19000=57748032 Coloumb

57748032=39.5\times t

t=1461975sec=406hours    (1hour=3600s)

Thus it will take 406 hours to plate 19.0 kg of copper onto the cathode if the current passed through the cell is held constant at 39.5 A

3 0
3 years ago
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