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svp [43]
4 years ago
12

Here is a more complex redox reaction involving the permanganate ion in acidic solution

Chemistry
1 answer:
guapka [62]4 years ago
8 0

Answer:

5NO2? + 6H+ + 2MnO4? ? 5NO3? +2Mn2+ + 3H2O

Explanation:

Classify each reactant as the reducing agent, oxidizing agent, or neither

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Which object in the solar system is shown in the image? (15 points)
valentinak56 [21]

Answer:

its an asteroid

and it seems to be same as picture and what I knew

have a great time

6 0
3 years ago
Do wind up clocks need batteries? -like the non wired ones.
Sphinxa [80]
No, why? Cause if you're winding up the clock it's basically doing what it needs to do. So there's no need for batteries.. I hope my sad sentence make sense :p
6 0
4 years ago
A satellite and a hockey puck are alike because they illustrate Newton's first law of motion.
lutik1710 [3]

Answer:

It would be True

Explanation:

Because they both have the same push of gravity. Gravity affects all objects equally. If you drop an egg and a watermelon at the same time they would both collide with the floor at the same time.

8 0
3 years ago
Mangrove trees are affected by several factors. Which is an abiotic factor contributing to the energy cycle of a mangrove ecosys
kondor19780726 [428]

Answer:

Just think of whats in a forest ecosystem

for example

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sunlight

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4 0
4 years ago
Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4
inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

M=\frac{n_{solute}}{V_{solution}}

So you can solve for the moles of the solute:

n_{solute}=M*V_{solution}

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

n_{solute}=1mol/L*1.5L=1.5mol

But this is just a supposition.

Regards.

4 0
3 years ago
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