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svp [43]
4 years ago
12

Here is a more complex redox reaction involving the permanganate ion in acidic solution

Chemistry
1 answer:
guapka [62]4 years ago
8 0

Answer:

5NO2? + 6H+ + 2MnO4? ? 5NO3? +2Mn2+ + 3H2O

Explanation:

Classify each reactant as the reducing agent, oxidizing agent, or neither

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The value of a scientific variable:
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Answer:

A

Explanation:

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during which step of the scientific method does a scientist make an educated guess about the outcome of an experiment
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hypothesis statement or the very beginning.

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Which of the following elements are already balanced in this equation? FeS₂ + Cl₂ → FeCl₃ + S₂ Cl₂
Anuta_ua [19.1K]

Fe and S are already balanced in this equation

<h3>Further explanation</h3>

Balanced indicates that the number of elements in question has the same number of atoms both on the left side (the number on the reactants side) and on the right side (the number on the product side)

Even though one of the elements is said to be balanced, the chemical equation as a whole cannot be said to be balanced, because the chemical equation has several components of the constituent elements.

To balance chemical equations, a coefficient in front of the compound is usually added either in the reactants or products

Reaction

FeS₂ + Cl₂ → FeCl₃ + S₂Cl₂

From this equation, it can be shown that: the Fe and S elements are balanced because the numbers are equal both on the left and right, while the Cl elements are not yet balanced

Fe, left=1, right=1 ⇒ balanced

S, left=2, right=1 ⇒ balanced

Cl, left=2, right=5⇒ not balanced

For balanced equations:

2FeS₂ + 5Cl₂ → 2FeCl₃ + 2S₂Cl₂

8 0
3 years ago
Benzoyl peroxide, the substance most widely used against acne, has a half-life of 9.8 × 103 days when refrigerated. How long wil
prohojiy [21]

Answer:

7.3\times 10^2\ days

Explanation:

Given that:

Half life = 9.8\times 10^3 days

t_{1/2}=\frac{\ln2}{k}

Where, k is rate constant

So,  

k=\frac{\ln2}{t_{1/2}}

k=\frac{\ln2}{9.8\times 10^3}\ days^{-1}

The rate constant, k = 0.00007 days⁻¹

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given:

5 % is lost which means that 0.05 of [A_0] is decomposed. So,

\frac {[A_t]}{[A_0]} = 1 - 0.05 = 0.95

t = ?

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.95=e^{-0.00007\times t}

t = 732.76 days = 7.3\times 10^2\ days

7 0
3 years ago
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