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Bad White [126]

3 years ago

8

if two substances have similar physical properties such as color and texture but different in other physical properties such as

boiling point or density what can you conclude about the two subtances?

1 answer:

blagie [28]3 years ago

3 0

Since they are made of different chemical make ups, boiling point and density they will most likely be in different groups on the periodic table.

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Which statement correctly lists the type of electromagnetic waves from highest to lowest energy? gamma rays, ultraviolet waves,

ahrayia [7]

Answer:

Thank you for posting your question on Brainly.

Explanation:

The waves from highest to lowest are :

* Gamma

* X- Rays

* UV

* Visible

* Infrared

* Microwaves

* Radio-waves

I really hope this was helpful. Have a great day : )

6 0

3 years ago

You push a 2.3 kg block against a horizontal spring, compressing the spring by 17 cm. then you release the block, and the spring

horsena [70]

Some dogs may inherit a susceptibility to epilepsy.

6 0

3 years ago

Someone help me please.

Soloha48 [4]

1/2*2.8*x^{2}=2.8*9.81*1.50

X=5.425

Because K.E=1/2*M*V² and it is equal to P.E in the conservation of energy which means its K.E=P.E

P.E=m*g*h

So K.E equals 1/2*2.8*(5.425)²=41.20

8 0

3 years ago

How long does it take (in seconds) a 80,000 W motor to do 3,000,000 J of work?

postnew [5]

P=W/t
t=W/P
t=3,000,000 / 80,000
t= 37.5 second

5 0

3 years ago

On a frictionless horizontal air table, puck A (with mass 0.252 kg ) is moving toward puck B (with mass 0.374 kg ), which is ini

geniusboy [140]

As we know that kinetic energy is given as

$KE = \frac{1}{2}mv^2$

Here we can find the initial speed of puck A by momentum conservation

$m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}$

$0.252\times v + 0 = 0.252\times (-0.115) + 0.374\times ( 0.650)$

$v = 0.850 m/s$

now here we will have initial kinetic energy of the mass is given as

$KE_i = \frac{1}{2}m_1v_1^2$

$KE_i = \frac{1}{2}(0.252)(0.850^2) = 0.091 J$

$KE_f = \frac{1}{2}(0.252)(-0.115)^2 + \frac{1}{2}(0.374)(0.650^2)$

$KE_f = 0.081 J$

now loss of energy is given as

$KE_i - KE_f = 0.091 - 0.081 = 0.010 J$

6 0

3 years ago