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4 years ago

Using the evidence provided, generate a pattern that describes the chemical reactivity of metals.

Chemistry

1 answer:

Afina-wow [57]4 years ago

7 0

Answer:

B)As you go from left to right, reactivity of metals increases. As you go down in a group, reactivity of metals decreases.

Explanation:

reactivity of metals can be explained as how it can easily lose electron, i.e oxidize as well as reaction with non-metals.

There are factors that influence the reactivity of metals such as

1)atomic radius

2)nuclear charge

3)shielding effect

4) The sublevel arrangement of electrons

In the periodic table,the group 1, known as alkali metals, are the most reactive metals

Therefore, as we from left to right, reactivity of metals increases. As we move down in a group, reactivity of metals decreases.

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0.75 atm. is the answer

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3 years ago

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Calcium dihydrogen phosphate, Ca(H₂PO₄)₂, and sodium hydrogen carbonate, NaHCO₃, are ingredients of baking powder that react to

NikAS [45]

0.012 mol of CO₂ can be produced from 3.50 g of baking powder.

<h3>What is baking powder?</h3>

Baking powder is a dry chemical leavener composed of carbonate or bicarbonate and a weak acid.
The addition of a buffer, such as cornstarch, prevents the base and acid from reacting prematurely.
Baking powder is used in baked goods to increase volume and lighten the texture.

To find how many moles of CO₂ are produced from 1.00 g of baking powder:

The balanced equation is:

Ca(H₂PO₄)₂(s) + 2NaHCO₃(s) → 2CO₂(g) + 2H₂O(g) + CaHPO₄(s) + Na₂HPO₄(s)

On 3.50 g of baking power:

mCa(H₂PO₄)₂ = 0.35 × 3.50 = 1.225 g
mNaHCO₃ = 0.31 × 3.50 = 1.085 g

The molar masses are: Ca = 40 g/mol; H = 1 g/mol; P = 31 g/mol; O = 16 g/mol; Na = 23 g/mol; C = 12 g/mol.

So,

Ca(H₂PO₄)₂: 40 + 4 × 1 + 31 + 8 × 16 = 203 g/mol
NaHCO₃: 23 + 1 + 12 + 3 × 16 = 84 g/mol

The number of moles is the mass divided by molar mass, so:

nCa(H₂PO₄)₂ = 1.225/203 = 0.006 mol
nNaHCO₃ = 1.085/84 = 0.0129 mol

First, let's find which reactant is limiting.

Testing for Ca(H₂PO₄)₂, the stoichiometry is:

1 mol of Ca(H₂PO₄)₂ ---------- 2 mol of NaHCO₃
0.006 of Ca(H₂PO₄)₂ -------- x

By a simple direct three rule:

x = 0.012 mol

So, NaHCO₃ is in excess.

The stoichiometry calculus must be done with the limiting reactant, then:

1 mol of Ca(H₂PO₄)₂ ------------- 2 mol of CO₂
0.006 of Ca(H₂PO₄)₂ -------- x

By a simple direct three rule:

x = 0.012 mol of CO₂

Therefore, 0.012 mol of CO₂ can be produced from 3.50 g of baking powder.

Know more about baking powder here:

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The correct question is given below:

Calcium dihydrogen phosphate, Ca(H2PO4)2, and sodium hydrogen carbonate, NaHCO3, are ingredients of baking powder that react with each other to produce CO2, which causes dough or batter to rise: Ca(H2PO4)2(s) + NaHCO3(s) → CO2(g) + H2O(g) + CaHPO4(s) + Na2HPO4(s)[unbalanced] If the baking powder contains 31.0% NaHCO3 and 35.0% Ca(H2PO4)2 by mass: (a) How many moles of CO2 are produced from 3.50 g of baking powder?

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2 years ago

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3 years ago

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Consider the following equation: K + Br → KBr. How many grams of KBr can you make with 1.25g of K?

Dmitry [639]

Answer:

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Explanation:

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3 years ago

Consider the following reversible reaction. What is the equilibrium constant expression for the given system?

ladessa [460]

The question is incomplete. Complete question is attached below
..........................................................................................................................

Answer:
Equilibrium constant (K) is defined as the ratio of concentration of product to concentration of reactant.

For the reaction: 2H2O(g) ↔ 2H2(g) + O2(g)

Equlibrium constant = $\frac{[H_2]^2[O_2]}{[H_20]^2}$

[ ] bracket in above expression indicates concentration.

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