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OlgaM077 [116]
3 years ago
12

There are eight black socks six blue socks and 14 White Socks in a drawer if one sock is randomly chosen from the drawer than wh

at is the probability that the sock Will not be blue?
Mathematics
2 answers:
zheka24 [161]3 years ago
6 0

Answer:

22/28 = 11/14

Step-by-step explanation:

no of socks other than blue = 22

total no of socks = 28

so probability= 22/28 = 11/14

postnew [5]3 years ago
5 0

Answer:

22

Step-by-step explanation:

8 black 6 blue and 14 white is equal to 28

and if 6 are blue the rest are not so 6-28=22

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Factor the greatest common factor from the polynomial 3x^2 + 6x -9
ryzh [129]

Answer:

3(x+3)(x -1)

Step-by-step explanation:

3x^2 + 6x -9

All the terms in this polynomial are divisible by 3. Factor 3 out of this polynomial:

= 3(x^2 + 2x -3)

Now, factor inside the parentheses by grouping:

= 3(x^2 -1x+3x -3)

We knew to split the +2x up into -1x and 3x because -1 and 3 multiply to get -3, which is the last value in the polynomial.

= 3(x(x -1)+3(x -1))\\= 3(x+3)(x -1)

Therefore, the final factored polynomial is 3(x+3)(x -1).

4 0
2 years ago
The sum of x and 3 times y is 5. The difference of x and y is 5. Write two equations and graph to find the value of y.
kupik [55]

Answer:

for the first one, x + 3 * y = 5

and the second equation, x - y = 5

Step-by-step explanation:

the sum of two numbers means for example the sum of 5 and 8 is 13, so as an equation that is 5 + 8 = 13

the difference is the same thing as the sum but it's subtraction.

and then times is just multiplication.

5 0
2 years ago
Find 85 - 72 x 4 ÷ 2 (13 - 11)
Lerok [7]

Answer:

13

Step-by-step explanation:

using BODMAS

13-11=2

SO 2*2=4

4/4=1

1*72=72

THEREFORE it is 85-72 =13

7 0
2 years ago
1. How much heat is absorbed by a 50g iron skillet when its temperature rises from 10oC to 124oC? Joules
hoa [83]
<span>1. How much heat is absorbed by a 50g iron skillet when its temperature rises from 10oC to 124oC? Joules

Formula: Heat = mass * specific heat * ΔT

Data:
mass = 50 g = 0.050 kg
specific heat of iron = 450 J/ kg °C
ΔT = 124°C - 10°C ¿ 114 °C

=> heat = 0.050kg * 450 J / kg°C * 114°C ≈ 2.6 J

2. If a refrigerator is a heat pump that follows the first law of thermodynamics, how much heat was removed from food inside of the refrigerator if it released 492J of energy to the room? Joules

The firs law of thermodynamics is conservation of energy => energy removed from inside of the refrigerator = energy released to the room

=> Answer = 492 J

3. How much heat is needed to raise the temperature of 45g of water by 63oC? Joules

Formula: heat = mass * specific heat * ΔT

specific heat of water = 4186 J / Kg °C

heat = 0.045 kg * 4186 J/kg °C * 63°C = 11,867.31 J
</span>
7 0
3 years ago
Answer please I’m dying from math
vovikov84 [41]

Step-by-step explanation:

It's C

I hope it helped:)

8 0
3 years ago
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