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3 years ago

Brainliest if answered in the next 5m

Chemistry

2 answers:

NNADVOKAT [17]3 years ago

7 0

Alchol is neither basic or acidic

iragen [17]3 years ago

4 0

Alcohol is a base because it has a pH level under 7. Readings of 7 and higher indicate that it is an acid, or alkaline, while readings below 7 indicate a base.

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what is the change in the velocity of the biker below as he travels from point b to point c ? ..... What is his acceleration fro

Furkat [3]

The change in the velocity = 4 m/s

Acceleration = 4 m/s²

<h3>Further explanation</h3>

Given

vo = initial velocity = 4 m/s

vf = final velocity = 8 m/s

t = 1 s

Required

The change in the velocity

Acceleration

Solution

the change in velocity =

$\tt vf-vo=8-4=4~m/s$

Acceleration = ratio of a change in velocity and the time

$\tt a=\dfrac{\Delta v}{t}= \dfrac{vf-vo}{t}$

Input the value :

$\tt a=\dfrac{4~m/s}{1~s}=4~m/s^2$

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3 years ago

What is the density of an object having a volume of 8 ml and a mass of 22 grams?

solniwko [45]

Answer:

0.32gcm3 . I miss the old Kanye, straight from the 'Go Kanye

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Explanation:

5 0

3 years ago

Read 2 more answers

What data should be plotted to show that experimental concentration data fits a first-order reaction? A) 1/[reactant] vs. time B

natita [175]

Answer:

C) In[reactant] vs. time

Explanation:

For a first order reaction the integrated rate law equation is:

$A = A_{0}e^{-kt}$

where A(0) = initial concentration of the reactant

A = concentration after time 't'

k = rate constant

Taking ln on both sides gives:

$ln[A] = ln[A]_{0}-kt$

Therefore a plot of ln[A] vs t should give a straight line with a slope = -k

Hence, ln[reactant] vs time should be plotted for a first order reaction.

7 0

3 years ago

Suppose 0.035 moles of HCl is dissolved in enough water to produce 750 mL of solution. What is the pH

zhuklara [117]

Answer:

pH = 1.33

Explanation:

Because HCl is a strong acid, each mole of HCl will completely dissociate into H⁺ and Cl⁻ species.

Now we calculate the molar concentration (molarity) of H⁺:

Molarity = moles / volume

(750 mL ⇒ 750 / 1000 = 0.750 L)

Molarity = 0.035 moles / 0.750 L

Molarity = 0.0467 M

Then we calculate the pH of the solution:

pH = -log [H⁺]

pH = -log (0.0467 M)

pH = 1.33

5 0

3 years ago

The Michaelis constant for pancreatic lipase is 5 mM. At 60 C, lipase is subject to deactivation with a half-life of 8 min. Fat

Dmitriy789 [7]

Explanation:

According to the given data, we will calculate the following.

Half life of lipase $t_{1/2}$ = 8 min x 60 s/min

= 480 s

Rate constant for first order reaction is as follows.

$k_{d} = \frac{0.6932}{480}$

= $1.44 \times 10^{-3}s^{-1}
$

Initial fat concentration $S_{o}$ = 45 $mol/m^{3}$

= 45 mmol/L

Rate of hydrolysis $V_m_{o}$ = 0.07 mmol/L/s

Conversion X = 0.80

Final concentration (S) = $S_{o} (1 - X)$

= 45 (1 - 0.80)

= 9 $mol/m^{3}$

or, = 9 mmol/L

It is given that $K_{m}$ = 5mmol/L

Therefore, time taken will be calculated as follows.

t = $-\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]$

Now, putting the given values into the above formula as follows.

t = $-\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]$

= $-\frac{1}{1.44 \times 10^{-3}s^{-1}}ln[1 - \frac{1.44 \times 10^{-3}s^{-1}}{0.07 mmol/L/s
}{K_{M} ln (\frac{45 mmol/L
}{9 mmol/L
}) + (45 mmol/L - 9 mmol/L
)]$

= $1642.83 s \times \frac{1 min}{60 sec}$

= 27.38 min

Therefore, we can conclude that time taken by the enzyme to hydrolyse 80% of the fat present is 27.38 min.

6 0

3 years ago