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nevsk [136]
3 years ago
9

Brainliest if answered in the next 5m

Chemistry
2 answers:
NNADVOKAT [17]3 years ago
7 0
Alchol is neither basic or acidic
iragen [17]3 years ago
4 0
Alcohol is a base because it has a pH level under 7. Readings of 7 and higher indicate that it is an acid, or alkaline, while readings below 7 indicate a base.
You might be interested in
A catalyst will
scZoUnD [109]

Answer:

increase the chemical rate

7 0
3 years ago
What mass of water will change its temperature by 3.0 0C when 525 J of heat is added to it? The specific heat of water is 4.184
pav-90 [236]

Answer:

Mass of water = 41.8 g

Explanation:

Given data:

Mass of water = ?

Change in temperature = 3.0 °C

Specific heat capacity = 4.184 j/g.°C

Heat absorbed = 525 j

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 3.0°C

Now we will put the values in formula.

525 J = m × 4.184 j/g.°C  × 3.0°C

525 J = m × 12.552 j/g

m =  525 J/ 12.552 j/g

m = 41.8 g

4 0
3 years ago
The amount of matter in a given amount of volume is referred to as
Damm [24]

Answer:

It would be Density because:

Density= mass/ volume

Density refers to the amount of matter or mass of a substance over a volume

7 0
3 years ago
What is the maximum amount in moles of P2O5P2O5 that can theoretically be made from 112 gg of O2O2 and excess phosphorus
Nastasia [14]

Answer:

n_{P_2O_5}^{max}=1.4molP_2O_5

Explanation:

Hello!

In this case, since the reaction between phosphorous and oxygen to form diphosphorous pentoxide is:

2P+\frac{5}{2}O_2\rightarrow P_2O_5

Thus, since phosphorous is in excess and oxygen and diphosphorous pentoxide are in a 5/2:1 mole ratio, we can compute the maximum moles of product as shown below:

n_{P_2O_5}^{max}=112 gO_2*\frac{1molO_2}{32.00gO_2}*\frac{1molP_2O_5}{5/2molO_2}\\\\  n_{P_2O_5}^{max}=1.4molP_2O_5

Best regards!

5 0
2 years ago
how much heat is released when 70.9g of water at 66C cools to 25C? The specific heat of water is 1 cal/gC
Serga [27]

Answer:

-12162.47 joules (or -12000 joules when accounting for significant figures)

Explanation (btw I used 1 cal as 4.184 joules because SI units are better):

q = m c delta T

q = (70.9) (4.184) (25 - 66)  

q = (70.9) (4.184) (-41)

q = -12162.47 joules

7 0
3 years ago
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