<span>64.94
First, write out an expression about what we know
0.6915 * 62.93 + 0.3085 * x = 63.55
Now solve for x
0.6915 * 62.93 + 0.3085 * x = 63.55
43.5161 + 0.3085 * x = 63.55
0.3085 * x = 20.03391
x = 64.93972
Rounding the answer to 2 decimal places gives x = 64.94</span>
Silver has to give up one electron in order to achieve a pseudo-noble gas electronic configuration.<span />
Iodine is a group 7A element. The halogens form anions because of their high electronegativities, so Iodine is unlikely to form a cation.
Answer:
O2, oxygen.
Explanation:
Hello.
In this case, for the undergoing chemical reaction, we need to compute the moles of CO2 yielded by 85 g of CH4 (molar mass = 16 g/mol) and by 320 g of O2 (molar mass 32 g/mol) via the following mole-mass relationships:

Considering the 1:2:1 among CH4, O2 and CO2. Therefore, since 320 g of O2 yield the smallest amount of CO2 we infer that the limiting reactant is O2.
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