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Vadim26 [7]
2 years ago
6

Help plssss The question is in the picture above

Chemistry
2 answers:
Paul [167]2 years ago
8 0

Answer:

The answer is : A

schepotkina [342]2 years ago
5 0

Answer:It is A

Explanation:

Because you a have a girl that knows everything

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Cesium has a radius of 272 pm and crystallizes in a body-centered cubic structure. What is the edge length of the unit cell
olchik [2.2K]

Answer: Edge length of the unit cell = 628pm

Explanation: For a body centred cubic structured system, the relationship between the edge length of the unit cell and radius of the atoms in the structure is

Edge length of Unit cell (a) = (4R)/(√3)

R = 272pm = (272 × (10^-12))m = (2.72 × (10^-10))m

a = (4 × (2.72 × (10^-10)))/(√3)

a = (6.28157 × (10^-10))m = 628pm

4 0
2 years ago
3. What is a double bond? Triple bond?
dsp73

Answer:

Double and triple covalent bonds occur when four or six electrons are shared between two atoms, and they are indicated in Lewis structures by drawing two or three lines connecting one atom to another

Explanation:

4 0
2 years ago
I NEED THE ANSWER IMMEDIATELY TONIGHT, PLEASE!!!
anzhelika [568]

Answer:

Ra,Ba,In,Sb,As,P hope this helps you out good luck

5 0
2 years ago
Nitric monoxide (NO) reacts with oxygen gas to form nitrogen dioxide (NO₂), a dark brown gas. If 5.895 mol of NO is mixed with 2
Schach [20]

Answer:

Limiting reactant: O2

grams NO2 produced = 230.276 g NO2

grams of NO unused = 26.67 gNO

Explanation:

2NO + O2 --> 2NO2

Step 1: Determine the molar ratio NO:O2

molar ratio NO:O2 = 5.895: 2.503 = 2.35

stoichiometric molar ratio NO:O2 = 2:1

So, O2 is the limiting reactant.

Step2: Determine the grams of NO2:

?g NO2 = moles O2 x (2moles NO2/1 mol O2) x (MM NO2/ 1 mol NO2) = 2.503 x 2 x 46 = 230.276 g NO2

Step 3: Determine the amount of excess reagent unreacted

moles excess NO reacted = moles O2 x (2 moles NO/1 mol O2) = 2.503 x 2 = 5.006 moles NO reacted

moles NO unreacted = total moles NO - moles NO reacted = 5.895-5.006 =0.889 moles NO unreacted

mass NO unreacted = moles NO unreacted x MM NO = 0.889 x 30 =26.67 g NO unreacted

8 0
2 years ago
What is the molarity of a 3.0-liter solution that contains 0.45 moles of solute
sergeinik [125]
Moles = n/v where n is the moles of solute and v being the liters of solution.
We can put in the information provided to find the molarity.

Moles = .45/3.0 = .15
So we now know that the molarity of that solution is .15!
 I hope I helped you :). Make sure to memorize that formula because it's not that hard as long as you know what to plug in.
6 0
2 years ago
Read 2 more answers
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