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lawyer [7]
3 years ago
9

A mixture of gaseous CO and H2, called synthesis gas, is used commercially to prepare methanol (CH3OH), a compound considered an

alternative fuel to gasoline. Under equilibrium conditions at 550.3 K, [H2] = 0.07710 mol/L, [CO] = 0.02722 mol/L, and [CH3OH] = 0.0401 mol/L. What is the value of Kc for this reaction at 550.3 K?
Chemistry
1 answer:
Anit [1.1K]3 years ago
3 0

<u>Answer:</u> The value of K_c for the reaction at 550.3 K is 247.83

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For a general chemical reaction:

aA+bB\rightarrow cC+dD

The expression for K_{c} is written as:

K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

The chemical equation for the production of methanol follows:

CO+2H_2\rightleftharpoons CH_3OH

The expression of K_c for above equation follows:

K_c=\frac{[CH_3OH]}{[CO][H_2]^2}

We are given:

[CH_3OH]=0.0401mol/L

[CO]=0.02722mol/L

[H_2]=0.07710mol/L

Putting values in above equation, we get:

K_c=\frac{0.0401}{0.02722\times (0.07710)^2}\\\\K_c=247.83

Hence, the value of K_c for the reaction at 550.3 K is 247.83

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