Answer:
ide is the correct answer
Explanation:
example compound of sodium and hydrogen in sodium hydroxide
and compound of hydrogen and chlorine is hydrogen chloride
Answer: 2.52*10^25
Explanation:
6.02214076*10^23 in 1 mole
Answer:
<h2>
32°F
/0°C
</h2>
Explanation:
At what temperature does the melting point occur?
32°F
/0°C
(32°F − 32) × 5/9 = 0°C
At temperatures above 32°F (0°C), pure water ice melts and changes state from a solid to a liquid (water); 32°F (0°C) is the melting point. For most substances, the melting and freezing points are about the same temperature.
Is Melting Point affected by temperature?
Melting point, the temperature at which the solid and liquid forms of a pure substance can exist in equilibrium. As heat is applied to a solid, its temperature will increase until the melting point is reached. More heat then will convert the solid into a liquid with no temperature change.
Answer:
No, It is not okay to pretend on social media.
Explanation:
No, it is not okay for people to post fake vacation pics and other fake info on social media. This is very wrong, as -
- This 'all time look good, feel good, have a happening life' approach of social media - implies showing only the positive side & not negative side of people's life. However, in real life is not a bed of roses.
- Faking things out implies that pretending to be cool has become more important than sharing deep meaningful relationships, & highlights superficial desire of false popularity.
- It is also harmful to people being communicated this fake image, as they might indulge into any social involvement, on the basis of unreal image of the concerned person.
Answer:
We need 8.7 mL of the stock solution
Explanation:
Step 1: Data given
Volume of the solution he wants to prepare = 50.0 mL = 0.050 L
Concentration of the solution he wants to prepare = 0.80 M
The concentration of the stock solution = 4.6 M
Step 2: Calculate the volume of the stock solution
C1*V1 = C2*V2
⇒with C1 = the concentration of the stock solution = 4.6 M
⇒with V1 = the volume of the stock solution = TO BE DETERMINED
⇒with C2 = the concentration of the prepared solution = 0.80 M
⇒with V2 = the volume of the prepared solution = 0.050 L
4.6 M * V2 = 0.80 M * 0.050 L
V2 = (0.80 M * 0.050 L) / 4.6M
V2 = 0.0087 L = 8.7 mL
We need 8.7 mL of the stock solution
