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Paraphin [41]
3 years ago
15

In general, atomic radii a. decrease from left to right in a period and increase down a group. b. increase from left to right in

a period and decrease down a group. c. do not change across a period or a group. d. decrease from left to right and decrease down a group. e. increase from left to right in a period and increase down a group
Chemistry
1 answer:
fomenos3 years ago
5 0

Answer: a. decrease from left to right in a period and increase down a group.

Explanation:

Atomic radius of an atom is defined as the total distance from the nucleus to the outermost shell of the atom.

As moving from left to right in a period, more and more electrons get added up in the same shell and the attraction between the last electron and nucleus increases, which results in the shrinkage of size of an atom. Thus, decreasing the atomic radii of the atom on moving towards right of the periodic table.

As moving from top to bottom in a group, there is an addition of shell around the nucleus and the outermost shell gets far away from the nucleus and hence, the distance between the nucleus and outermost shell increases. Thus, increasing the atomic radii of the atom.

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A scientist measures the standard enthalpy change for the following reaction to be -327.2 kJ : P4O10(s) 6 H2O(l)4H3PO4(aq) Based
OleMash [197]

Answer:

ΔH°f P4O10(s) = - 3115.795 KJ/mol

Explanation:

  • P4O10(s) + 6H2O(l) ↔ 4H3PO4(aq)
  • ΔH°rxn = ∑νiΔH°fi

∴ ΔH°rxn = - 327.2 KJ

∴ ΔH°f H2O(l) = - 285.84 KJ/mol

∴ ΔH°F H3PO4(aq) = - 1289.5088 KJ/mol

⇒ ΔH°rxn = (4)(- 1289.5088) - (6)(- 285.84) - ΔH°f P4O10(s) = - 327.2 KJ

⇒ ΔH°f P4O10(s) = - 5158.035 + 1715.04 + 327.2

⇒ ΔH°f P4O10(s) = - 3115.795 KJ/mol

5 0
3 years ago
at a given tempature gas with a pressure of 150 kpa has volume of 0.8 l if the pressure decreases to 75kpa and the temperature r
vova2212 [387]
  <span>P*V/T=constant 
so P*V= constant*T 
if T doesn't change then 
P*V= constant 
so 150kPa*0.8L=75kPa*xL 
xL=150kPa*0.8L/75kPa=1.6L 
hope it help</span>
8 0
3 years ago
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