This is false because it doesn't matter about the mass
Answer:
P(total pressure) = 504 mmHg = 504mm/760mm/atm = 0.663 atm
Explanation:
Apply Dalton's Law of Partial Pressures.
P(total) = ∑Partial Pressures = ∑(256mm + 198mm + 48mm) = 504 mmHg
P(total pressure) = 504 mmHg = 504mm/760mm/atm = 0.663 atm
Answer : The normal boiling point of ethanol will be, 
or 
Explanation :
The Clausius- Clapeyron equation is :
where,
= vapor pressure of ethanol at 
= 98.5 mmHg
= vapor pressure of ethanol at normal boiling point = 1 atm = 760 mmHg
= temperature of ethanol = 
= normal boiling point of ethanol = ?
= heat of vaporization = 39.3 kJ/mole = 39300 J/mole
R = universal constant = 8.314 J/K.mole
Now put all the given values in the above formula, we get:
Hence, the normal boiling point of ethanol will be, or
The density of He is 1.79 x 10⁻⁴ g/mL
In other words in 1 mL there's 1.79 x 10⁻⁴ g of He.
To fill a volume of 6.3 L the mass of He required
= 1.79 x 10⁻⁴ g/mL * 6300 mL
= 11 277 * 10⁻⁴ g
Therefore mass of He required = 1.1277 g of He
B) energy is absorbed by the reaction
is right answer.
