Explanation:
The ratio of NH3 to NO produced will remain constant since NH3 is the limiting reactant.
Here in this reaction for every 4 moles of ammonia and 5 moles of oxygen gas , 4 moles of NO and 6 moles of water are formed.
So when the amount of oxygen gas is increased to 20 moles without changing the amount of ammonia , the amount of NO formed does not increase as ammonia becomes the limiting reactant.
Answer:
7.22L
Explanation:
At Stp T2 = 273K and P2 is 1 atm
So we have the following data
V1 =10L. P1=650mmHg(0.855atm)
V2 =V2. P2 = 1 atm
T1=50°c (323K) T2 =273K
Hence from the combined gas law
P1xV1 /T1 =P2xV2/T2
0.855x10/323 =1xV2 /273
8.55/323 =V2 /273
V2 = 8.55x273 /323
V2 = 7.226 L
