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3 years ago

What causes damage to the ozone layer?

Physics

1 answer:

irga5000 [103]3 years ago

4 0

Answer:

Chlorofluorocarbons (CFC's)

Explanation:

The substances that are the most responsible for the damage done on the ozone layer are the chlorofluorocarbons (CFC's). The CFC's are very light, so they get up into the atmosphere with ease. While they are in the lower part of the atmosphere they do not cause any particular problems as the UV radiation is very limited, but that all changes when they reach the ozone layer. Once they reach the ozone layer in the stratosphere, the CFC's are exposed to much stronger UV radiation. This causes them to dissociate and release chlorine atoms. Once this has happened, these atoms manage to break down the bond between the oxygen atoms, thus destroying the ozone layer.

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With time running out in a game, Rachel runs towards the basket at a speed of 2.5 meters per second and from half-court, launche

finlep [7]

Answer:

Rachel(2.5,0)

ball(6.5,4.7)

b.R=10.15m/s, 27.57deg

Explanation:

The reference angle of Rachel is 0 $0^{0} while the ball is at 36^{0}$

resolving rachel's speed to the horizontal, we have

Ux=2.5cos0

Ux=2.5m/s

resolving rachel's speed to the vertical we have,

Uy=2.5sin0

Uy=0

for the ball

resolving the speed to its horizontal component

Ux=8cos36

Ux=6.5m/s

Uy=8sin36

Uy=4.7m/s

Rachel(2.5,0)

ball(6.5,4.7)

To get the resultant of their speed

Add the horizontal speed of rachel to that of the ball to get the total horizontal speed

Add the vertical speed of rachel and the ball to get the total vertical speed component

TUx=2.5+6.5=9M/S

TUy=0+4.7=4.7m/s

R= $\sqrt{(TUx^2+TUy^2}$

R= $\sqrt{(9^2+4.7^2}$

R= $\sqrt{(103)}$

R=10.15m/s

the direction

tan $\alpha$ =TUy/TUx

tan $\alpha$ =4.7/9

$\alpha$ =tan^-1(0.522)

$\alpha$ =27.57deg

4 0

3 years ago

This is the answer for the questions good luck

melamori03 [73]

The reason meow is because meow meow meow meow meow meow of 4 meow.

7 0

2 years ago

8. In the billiard ball room at the basement of Memorial Union, two identical balls are traveling toward each other along a stra

mel-nik [20]

Answer:

- Ball 1 will move backward at 7.89 m/s

- Ball 2 will move forward at 4.67 m/s

Explanation:

In an elastic collision, both the total momentum and the total kinetic energy of the system are conserved.

The conservation of the momentum can be written as:

$m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2$

where

$m_1$ is the mass of ball 1

$m_2$ is the mass of ball 2

$u_1$ is the initial velocity of ball 1

$u_2$ is the initial velocity of ball 2

$v_1$ is the final velocity of ball 1

$v_2$ is the final velocity of ball 2

The conservation of kinetic energy can be written as

$\frac{1}{2}m_1 u_2^2 + \frac{1}{2}m_2 u_2^2 = \frac{1}{2}m_1 v_1^2 + \frac{1}{2}m_2 v_2^2$

Working together the two equations, it is possible to find two expressions for the final velocities in terms of the initial velocities:

$v_1=\frac{m_1 -m_2}{m_1 +m_2}u_1+\frac{2m_2}{m_1+m_2}u_2\\v_2=\frac{2m_1}{m_1+m_2}u_1 -\frac{m_1 -m_2}{m_1 +m_2}u_2$

In this problem we have:

$m_1 = m_2 = m$ since the mass of the two balls is identical

$u_1=+4.67 m/s$ is the initial velocity of ball 1

$u_2=-7.89 m/s$ is the initial velocity of ball 2

Substituting into the equations, we find the final velocities:

$v_1=\frac{2m}{m+m}u_2=u_2 =-7.89 m/s\\v_2=\frac{2m}{m+m}u_1=u_1=+4.67 m/s$

Therefore:

- Ball 1 will move backward at 7.89 m/s

- Ball 2 will move forward at 4.67 m/s

7 0

3 years ago

1000 kg has 50, 000 joules of kinetic energy. what is it's speed?

kicyunya [14]

The answer is 36 kilometers per hour, or 10 meters per second.

7 0

3 years ago

A uniform solid sphere rolls down an incline.

SashulF [63]

Answer with Explanation:

We are given that

a.Linear acceleration,a=0.1 g

Moment of inertia of solid sphere, $I=\frac{2}{5}mr^2$

We know that

$a=\frac{gsin\theta}{1+\frac{I}{mr^2}}$

Using the formula

$0.1g=\frac{gsin\theta}{1+\frac{2mr^2}{5mr^2}}$

$0.1(1+\frac{2}{5})=sin\theta$

$sin\theta=0.1\times \frac{7}{5}=0.14$

$\theta=sin^{-1}(0.14)=8.05^{\circ}$

b.When a frictionless block were to slide down the incline at that angle then the motion of block will be linear .There is no rotation.

When the sphere is moving without rotation then, the linear speed of sphere will be larger.

When the linear speed is larger then, the linear acceleration will be larger.

Hence, the magnitude of acceleration will be more.

7 0

4 years ago