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DochEvi [55]
3 years ago
10

How many grams of NaOH would be needed to make 0.50 L of a 1.25 molar NaOH solution

Chemistry
1 answer:
Likurg_2 [28]3 years ago
3 0

The solution would be made by dissolving 4 grams NaOH in .5 Liters of H2O
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On the reaction below, label the BSA, BSB, CA, and CB. CH3COOH + H2O → CH3COO– + H3O+
Ostrovityanka [42]

Answer:

Acid(BSA) = CH₃COOH

Base (BSB) = H₂O

Conjugate base (CB) = CH₃COO⁻

Conjugate acid (CA) = H₃O⁺

Explanation:

Equation of reaction;

CH₃COOH + H₂O → CH₃COO⁻ + H₃O⁺

Hello,

From my understanding of the question, we are required to identify the

1) Acid

2) Base

3) conjugate acid

4) conjugate base in the reaction

Acid (BSA) = CH₃COOH

Base (BSB) = H₂O

CA = conjugate acid = H₃O⁺

CB = conjugate base = CH₃COO⁻

7 0
3 years ago
Which best describes a difference between energy transformation in power plants and dams?
gogolik [260]

Answer:

Which best describes a difference between energy transformations in power plants and dams? Only power plants use fossil fuels to transform energy. Only dams use fission to generate thermal energy. ... Only dams use mechanical energy to produce electricity.

Explanation:

HOPE THIS HELP

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6 0
3 years ago
The compound 1-iodododecane is a nonvolatile liquid with a density of 1.20g/ml. the density of mercury is 13.6g/ml. part a what
valina [46]

As the atmospheric pressure is, P = dgh

Here d is the density of the mercury,

g is gravitation = 9.8 m/s²

h is height of the column, P = 751 torr = (751 torr × 1 atm / 760 torr) (101325 Pa) (1 N/m² / 1 Pa) = 100125 N/m²

Where, 1 N = 1 Kg / ms²

Thus, P = 100125 Kg / m³. s²

Therefore, height of the mercury column, when the atmospheric pressure is 751 torr,

h = P / gd

= (100125 kg / m³. s²) / (9.8 m/s²) (13.6 × 10³ kg / m³) = 0.751 m

As, d₁h₁ = d₂h₂

Here, d₁ is the density of the non-volatile liquid = 1.20 g/ml

d₂ is the density of the mercury = 13.6 g/ml

h₂ = 0.751 m

Thus, putting the values we get,

h₁ = d₂h₂ /d₁ = 13.6 g/ml × 0.751 m / 1.20 g/ml

= 8.5 m


3 0
3 years ago
How many grams of water (H2O) are produced from 34 grams of oxygen (O2)? *
Dennis_Churaev [7]

Answer:

Explanation:

complete combustion reaction of  ethane is given by the reaction

2C2H6+7O2..............4CO2+6H2O

no of moles in 34 grams of O2=34/32=1.063

7mole of O2 produced 6 moles of H2O

therefore 1.063 moles of O2 produced=1.063*6/7=0.9 moles

now 0.9 moles of H2O contain how much grams=0.9*18=16.2 grams

3 0
3 years ago
Hows everyone doing? tell me about your day in the comments thingy. mine aint going so great :/
GarryVolchara [31]

Answer:

Mine is doing good since I dont have any school today it makes it better. Im listening to scary stories on YT right now which always makes my day better so Im having a really good day today!

What about you? Why isn't your day doing so great?

6 0
3 years ago
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