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DochEvi [55]
3 years ago
10

How many grams of NaOH would be needed to make 0.50 L of a 1.25 molar NaOH solution

Chemistry
1 answer:
Likurg_2 [28]3 years ago
3 0

The solution would be made by dissolving 4 grams NaOH in .5 Liters of H2O
You might be interested in
How much energy in joules is released when 18.5 grams of copper cools from 285 °C<br> down to 45 °C
nadya68 [22]

Answer: 1709.4 Joules

Explanation:

The quantity of Heat Energy (Q) released on cooling a heated substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since Q = ?

M = 18.5 grams

Recall that the specific heat capacity of copper C = 0.385 J/g.C

Φ = 285°C - 45°C = 240°C

Then, Q = MCΦ

Q = 18.5grams x 0.385 J/g.C x 240°C

Q = 1709.4 Joules

Thus, 1709.4 Joules is released when copper is cooled.

5 0
3 years ago
How many moles of Ag will be produced from 16.0 g of Cu, assuming AgNO3 is available in excess
madreJ [45]

Answer:0.504

Explanation:

4 0
3 years ago
Who was the first scientist to measure speed as distance over time?
777dan777 [17]

Galileo was the first scientist to measure speed as distance over time.

8 0
3 years ago
Holding temperature and pressure constant, what is the most important feature in determining the phase of a given organic compou
Leni [432]
Holding temperature and pressure constant <span>the most important feature in determining the phase of a given organic compound is pressure. ransfers of organic compounds between phases are controlled by molecular interactions (intermolecular bonding) in the two phases between which transfer is occurring. This is governed by temperature and pressure</span>
3 0
3 years ago
Read 2 more answers
#2: A gas at unknown pressure and a volume of 66 cm has its pressure changed to 150 kPa. The new volume
Murljashka [212]

Answer:

<h2>377 kPa</h2>

Explanation:

The original pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the original pressure

P_1 =  \frac{P_2V_2}{V_1}  \\

150 kPa = 150,000 Pa

We have

P_1 =  \frac{150000 \times 166}{66}  =  \frac{24900000}{66}  \\  = 377272.72...

We have the final answer as

<h3>377 kPa</h3>

Hope this helps you

7 0
3 years ago
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